bài 1: Tìm X
a, 0 : x = 0
b, 12 x ( x-1 ) = 0
c, (x-17) – 115=0
d, 315 + ( 146 – x ) = 401
e, x – 36 : 18 = 12
f, ( x – 36 ) : 18 + 12
Mong MN giúp đỡ
bài 1: Tìm X a, 0 : x = 0 b, 12 x ( x-1 ) = 0 c, (x-17) – 115=0 d, 315 + ( 146 – x ) = 401 e, x – 36 : 18 = 12 f, ( x – 36 ) : 18 + 12
By Ayla
a, 0 : x = 0
x = 0:0
x = 0
b, 12 x ( x-1 ) = 0
x-1 = 0:12
x-1 = 0
x = 0+1
x = 1
c, (x-17) – 115=0
x-17 =0+115
x-17 =115
x =115+17
x = 132
d, 315 + ( 146 – x ) = 401
146 – x =401-315
146 – x =86
x =146-86
x = 60
e, x – 36 : 18 = 12
x – 2 =12
x =12+2
x =14
f, ( x – 36 ) : 18 = 12
x – 36 = 12×18
x – 36 =216
x =216+36
x =252
`a, 0 : x = 0`
`⇔ x ∈ N`*
`b, 12x(x – 1) = 0`
`⇔` \(\left[ \begin{array}{l}12x=0\\x-1=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=0\\x=1\end{array} \right.\)
`c, (x – 17) – 115 = 0`
`⇔ x – 17 = 115`
`⇔ x = 115 + 17`
`⇔ x = 132`
`d, 315 + (146 – x) = 401`
`⇔ 146 – x = 401 – 315`
`⇔ 146 – x = 86`
`⇔ x = 146 – 86`
`⇔ x = 60`
`e, x – 36 : 18 = 12`
`⇔ x – 2 = 12`
`⇔ x = 12 + 2`
`⇔ x = 14`
`f, (x – 36) : 18 = 12`
`⇔ x – 36 = 12 . 18`
`⇔ x – 36 = 216`
`⇔ x = 216 + 36`
`⇔ x = 252`