CH4 + CL2 —>
C2H4 + Br2 —>
C2H4 + O2 —>
CH3COOH + NAOH —>
C2H5OH + NA —>
CH3COOH + KOH —>
CH4 + O2 —>
CH3COOH + Na2O —>
CH3COOH + CaO —>
CH3COOH + K2O —>
CH3COOH + C2H5OH —>
Cân bằng phương trình hóa học giúp mình với ạ
CH4 + CL2 —> C2H4 + Br2 —> C2H4 + O2 —> CH3COOH + NAOH —> C2H5OH + NA —> CH3COOH + KOH —> CH4 + O2 —> CH3COOH + Na2O —> CH3COOH + CaO
By Adeline
Đáp án:
Giải thích các bước giải:
a) CH₄ + Cl₂ —as–> CH₃Cl + HCl
b) C₂H₄ + Br₂—–> CH₂Br + CH₂Br
c) C₂H₄ + 3O₂ —t°—> 2CO₂ + 2H₂O
d)CH₃COOH+NaOH —>CH₃COONa+H₂O
e) 2C₂H₅OH +2 Na —-> 2C₂H₅ONa + H₂↑
f)CH₃COOH+KOH —-> CH₃COOK + H₂O
g) CH₄ + 2O₂ —–t°–> CO₂ + 2H₂O
h 2CH₃COOH+Na₂O—>2CH₂COONa+H₂O
i2CH₃COOH+CaO —>(CH₃COO)₂Ca+H₂O
k)2CH₃COOH+K₂O –> 2CH₃COOK + H₂O
l) CH₃COOH + C₂H₅OH ⇄CH₃COOC₂H₅+H₂O
$CH_4+Cl_2\buildrel{{as}}\over\to CH_3Cl+HCl$
$C_2H_4+Br_2\to C_2H_4Br_2$
$C_2H_4+3O_2\buildrel{{t^o}}\over\to 2CO_2+2H_2O$
$CH_3COOH+NaOH\to CH_3COONa+H_2O$
$2C_2H_5OH+2Na\to 2C_2H_5ONa+H_2$
$CH_3COOH+KOH\to CH_3COOK+H_2O$
$CH_4+2O_2\buildrel{{t^o}}\over\to CO_2+2H_2O$
$2CH_3COOH+Na_2O\to 2CH_3COONa+H_2O$
$2CH_3COOH+CaO\to (CH_3COO)_2Ca+H_2O$
$2CH_3COOH+K_2O\to 2CH_3COOK+H_2O$
$CH_3COOH+C_2H_5OH\buildrel{{t^o, H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$