Toán Giúp mik với ạ!! 1/4+1/3: |2 x-1 |=11/12 03/08/2021 By Aaliyah Giúp mik với ạ!! 1/4+1/3: |2 x-1 |=11/12
$\frac{1}{4}$+$\frac{1}{3}$ : |2 x-1 |=$\frac{11}{12}$ $\frac{1}{3}$ : |2 x-1 | =$\frac{11}{12}$ -$\frac{1}{4}$ $\frac{1}{3}$ : |2 x-1 | =$\frac{2}{3}$ |2 x-1 | = $\frac{1}{3}$ :$\frac{2}{3}$ |2 x-1 | =$\frac{1}{2}$ ⇒2x-1 =$\frac{1}{2}$ hoặc 2x-1 =-$\frac{1}{2}$ TH1:2x-1 =$\frac{1}{2}$ 2x=$\frac{1}{2}$+1 2x=$\frac{3}{2}$ x=$\frac{3}{2}$:2 x=$\frac{3}{4}$ TH2:2x-1 =-$\frac{1}{2}$ 2x=-$\frac{1}{2}$+1 2x=$\frac{1}{2}$ x=$\frac{1}{2}$:2 x=$\frac{1}{4}$ vậy x∈{$\frac{1}{4}$;$\frac{3}{4}$} Trả lời
$\frac{1}{4}$ + $\frac{1}{3}$ : |2x-1|=$\frac{11}{12}$ $\frac{1}{3}$ : |2x-1| = $\frac{11}{12}$ – $\frac{1}{4}$ $\frac{1}{3}$ : |2x-1| = $\frac{2}{3}$ |2x-1| = $\frac{1}{3}$ : $\frac{2}{3}$ |2x-1| = $\frac{1}{2}$ ⇒\(\left[ \begin{array}{l}2x-1=\frac{1}{2} \\2x-1 = \frac{-1}{2} \end{array} \right.\) ⇒\(\left[ \begin{array}{l}2x = \frac{3}{2} \\2x = \frac{1}{2} \end{array} \right.\) ⇒\(\left[ \begin{array}{l}x= \frac{3}{4} \\x = \frac{1}{4} \end{array} \right.\) vậy \(\left[ \begin{array}{l}x= \frac{3}{4} \\x=\frac{1}{4} \end{array} \right.\) Trả lời
$\frac{1}{4}$+$\frac{1}{3}$ : |2 x-1 |=$\frac{11}{12}$
$\frac{1}{3}$ : |2 x-1 | =$\frac{11}{12}$ -$\frac{1}{4}$
$\frac{1}{3}$ : |2 x-1 | =$\frac{2}{3}$
|2 x-1 | = $\frac{1}{3}$ :$\frac{2}{3}$
|2 x-1 | =$\frac{1}{2}$
⇒2x-1 =$\frac{1}{2}$ hoặc 2x-1 =-$\frac{1}{2}$
TH1:2x-1 =$\frac{1}{2}$
2x=$\frac{1}{2}$+1
2x=$\frac{3}{2}$
x=$\frac{3}{2}$:2
x=$\frac{3}{4}$
TH2:2x-1 =-$\frac{1}{2}$
2x=-$\frac{1}{2}$+1
2x=$\frac{1}{2}$
x=$\frac{1}{2}$:2
x=$\frac{1}{4}$
vậy x∈{$\frac{1}{4}$;$\frac{3}{4}$}
$\frac{1}{4}$ + $\frac{1}{3}$ : |2x-1|=$\frac{11}{12}$
$\frac{1}{3}$ : |2x-1| = $\frac{11}{12}$ – $\frac{1}{4}$
$\frac{1}{3}$ : |2x-1| = $\frac{2}{3}$
|2x-1| = $\frac{1}{3}$ : $\frac{2}{3}$
|2x-1| = $\frac{1}{2}$
⇒\(\left[ \begin{array}{l}2x-1=\frac{1}{2} \\2x-1 = \frac{-1}{2} \end{array} \right.\)
⇒\(\left[ \begin{array}{l}2x = \frac{3}{2} \\2x = \frac{1}{2} \end{array} \right.\)
⇒\(\left[ \begin{array}{l}x= \frac{3}{4} \\x = \frac{1}{4} \end{array} \right.\)
vậy \(\left[ \begin{array}{l}x= \frac{3}{4} \\x=\frac{1}{4} \end{array} \right.\)