Toán N = x ^4 + 2x ^3y – 2x ^3 + x ^2y^2 – 2x ^2y – x ( x + y ) + 2x + 3 08/09/2021 By Valerie N = x ^4 + 2x ^3y – 2x ^3 + x ^2y^2 – 2x ^2y – x ( x + y ) + 2x + 3
*Lời giải : `N = x^4 + 2x^3y – 2x^3 + x^2y^2 – 2x^2y – x (x + y) + 2x + 3` `-> N = x^4 + 2x^3y – 2x^3 + x^2y^2 – 2x^2y – x^2 + xy + 2x + 3` Trả lời
*Lời giải :
`N = x^4 + 2x^3y – 2x^3 + x^2y^2 – 2x^2y – x (x + y) + 2x + 3`
`-> N = x^4 + 2x^3y – 2x^3 + x^2y^2 – 2x^2y – x^2 + xy + 2x + 3`