Phân tích các đa thức sau thành nhân tử: a) (3x-1)^2 – 16 b) (5x-4)^2 -49x² d) (3x +1)^2– 4(x – 2)^2 g) (ax + by)^2 – (ay + bx)² i) (4x² – 3x – 18)² –

Question

Phân tích các đa thức sau thành nhân tử:
a) (3x-1)^2 – 16
b) (5x-4)^2 -49x²
d) (3x +1)^2– 4(x – 2)^2
g) (ax + by)^2 – (ay + bx)²
i) (4x² – 3x – 18)² – (4x² +3x)²
I) -4^2 +12xy –9y² +25
c) (2x +5)^2 -(x-9) ²

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Audrey 1 tháng 2021-08-04T20:01:00+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-08-04T20:02:31+00:00

    a, (3x-1)²-16

    = (3x-1)²-4²

    = (3x-1-4)(3x-1+4)

    = (3x-5)(3x+3) 

    b, (5x-4)²-49x²

    = (5x-4)²-(7x)²

    = (5x-4-7x)(5x-4+7x)

    =(-2x-4)(12x-4)

    d, (3x+1)²-4(x-2)²

    = (3x+1)²-[2(x-2)]²

    = [3x+1-2(x-2)][3x+1+2(x-2)]

    = (3x+1-2x+4)(3x+1+2x-4)

    = (x+5)(5x-3)

    g, (ax+by)²-(ay+bx)²

    = (ax+by-ay-bx)(ax+by+ay+bx)

    i, (4x²-3x-18)²-(4x²+3x)²

    = (4x²-3x-18-4x²-3x)(4x²-3x-18+4x²+3x)

    = (-6x-18)(8x²-18)

    l, 4x²+12xy-9y²-25

    = (4x²-12xy+9y²)-25

    = (2x-3y)²-5²

    = (2x-3y-5)(2x-3y+5)

    c, (2x+5)²-(x-9)²

    = (2x+5-x+9)(2x+5+x-9)

    = (x+14)(3x-4)

     

    0
    2021-08-04T20:02:57+00:00

    `a, (3x-1)²-16`

    `= (3x-1)²-4²`

    `= (3x-5)(3x+3)`

    `b, (5x-4)²-49x²`

    `= (5x-4)²-(7x)²`

    `=(-2x-4)(12x-4)`

    `d, (3x+1)²-4(x-2)²`

    `= (3x+1)²-[2(x-2)]²`

    `= [3x+1-2(x-2)][3x+1+2(x-2)]`

    `= (x+5)(5x-3)`

    `g, (ax+by)²-(ay+bx)²`

    `= (ax+by-ay-bx)(ax+by+ay+bx)`

    `i, (4x²-3x-18)²-(4x²+3x)²`

    `= (4x²-3x-18-4x²-3x)(4x²-3x-18+4x²+3x)`

    `= (-6x-18)(8x²-18)`

    `l, 4x²+12xy-9y²-25`

    `= (4x²-12xy+9y²)-25`

    `= (2x-3y)²-5²`

    `= (2x-3y-5)(2x-3y+5)`

    `c, (2x+5)²-(x-9)²`

    `= (x+14)(3x-4)`

     Xin hay nhất !

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