Thực hiện sơ đồ biến hóa sau 1. C2H5OH -> C2H4 -> CH3-CHO -> C2H5-OH -> CH3-COOH 2. C2H4 -> C2H5OH -> CH3-CHO -> CH3-COOH -> CH3-COO-C2H5

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1. 1) 

   \({C_2}{H_5}OH\xrightarrow{{{H_2}S{O_4},{t^o}}}{C_2}{H_4} + {H_2}O\)

   \({C_2}{H_4} + \frac{1}{2}{O_2}\xrightarrow{{xt}}C{H_3}CHO\)

   \(C{H_3}CHO + {H_2}\xrightarrow{{Ni,{t^o}}}{C_2}{H_5}OH\)

   \({C_2}{H_5}OH + {O_2}\xrightarrow{{men}}C{H_3}COOH + {H_2}O\)

   2) 

   \({C_2}{H_4} + {H_2}O\xrightarrow{{{H^ + }}}{C_2}{H_5}OH\)

   \({C_2}{H_5}OH + CuO\xrightarrow{{{t^o}}}C{H_3}CHO + Cu + {H_2}O\)

   \(C{H_3}CHO + \frac{1}{2}{O_2}\xrightarrow{{xt}}C{H_3}COOH\)

   \(C{H_3}COOH + {C_2}{H_5}OH\xrightarrow{{{t^o}}}C{H_3}COO{C_2}{H_5} + {H_2}O\)

   Trả lời

2. Đáp án:

   CÂU 1:

   $C2H5OH -H2SO4đ, 170^{o}C-> C2H4 + H2O$

   $C2H4 + 1/2O2 -xt-> CH3CHO$

   $CH3CHO + H2 -Ni, to-> C2H5OH$

   $C2H5OH + O2 -MG-> CH3COOH + H2O$

   CÂU 2:

   $C2H4 + H2O -H2SO4đ, to-> C2H5OH$

   $C2H5OH + CuO -to-> CH3CHO + Cu + H2O$

   $CH3CHO + 1/2O2 -xt-> CH3COOH$

   $CH3COOH + C2H5OH <-H2SO4đ, 140^{o}C-> CH3COOC2H5 + H2O$

    

   Trả lời