Toán tìm x: a,/x-4/+3=2 b,x-1>3 c,1-3x>4 d,3-4x<5 05/08/2021 By Genesis tìm x: a,/x-4/+3=2 b,x-1>3 c,1-3x>4 d,3-4x<5
a) lx-4l + 3 = 2 lx-4l = 2 – 3 lx-4l = -1 Mà giá trị tuyệt đối luôn ≥ 0 ⇒ x ∈ ∅ Vậy x ∈ ∅ b) x – 1 > 3 x > 3 + 1 x > 4 Vậy x > 4 c) 1 – 3x > 4 3x > -3 x > -1 Vậy x > -1 d) 3 – 4x < 5 4x < 2 x < 2 Vậy x < 2 ~Good luck~ Trả lời
a) $|x-4|+3=2$ $|x-4|=-1$ $→x∈∅$ ($|x-4|≥0$) b) $x-1>3$ $x>3+1$ $x>4$ c) $1-3x>4$ $3x>1-4$ $3x>-3$ $x>-\dfrac{3}{3}=-1$ d) $3-4x<5$ $4x<3-5=-2$ $x<-\dfrac{2}{4}=-\dfrac{1}{2}$ Trả lời
a) lx-4l + 3 = 2
lx-4l = 2 – 3
lx-4l = -1
Mà giá trị tuyệt đối luôn ≥ 0 ⇒ x ∈ ∅
Vậy x ∈ ∅
b) x – 1 > 3
x > 3 + 1
x > 4
Vậy x > 4
c) 1 – 3x > 4
3x > -3
x > -1
Vậy x > -1
d) 3 – 4x < 5
4x < 2
x < 2
Vậy x < 2
~Good luck~
a) $|x-4|+3=2$
$|x-4|=-1$
$→x∈∅$ ($|x-4|≥0$)
b) $x-1>3$
$x>3+1$
$x>4$
c) $1-3x>4$
$3x>1-4$
$3x>-3$
$x>-\dfrac{3}{3}=-1$
d) $3-4x<5$
$4x<3-5=-2$
$x<-\dfrac{2}{4}=-\dfrac{1}{2}$