rút gọn: 4^30.27^10+8^20.3^29):(6^30.2^25) CẢM ƠN TRƯỚC NHA 04/07/2021 Bởi Vivian rút gọn: 4^30.27^10+8^20.3^29):(6^30.2^25) CẢM ƠN TRƯỚC NHA
`{4^30. 27^10+8^20. 3^29}/{6^30. 2^25}``={(2^2)^30. (3^3)^10+(2^3)^20. 3^29}/{(2.3)^30. 2^25}``={2^60. 3^30+2^60. 3^29}/{2^30. 3^30. 2^25}``={2^60. 3^30+2^60. 3^29}/{2^55. 3^30}``={2^55. 3^29(2^5. 3+2^5)}/{2^55. 3^29. 3}``={2^55. 3^29. 128}/{2^55. 3^29. 3}``=128/3` Bình luận
Đáp án: $\dfrac{128}{3}$ Giải thích các bước giải:$($ $4^{30}$ $.$ $27^{10}$ $+$ $8^{20}$ $.$ $3^{29}$ $)$ $:$ $($ $6^{30}$ $.$ $2^{25}$ $)$$→$ $\dfrac{4^{30} . 27^{10} + 8^{20} . 3^{29}}{6^{30} . 2^{25}}$$→$ $\dfrac{(2^{2})^{30} . (3^{3})^{10} + (2^{3})^{20} . 3^{29}}{(2.3)^{30} . 2^{25}}$$→$ $\dfrac{2^{60} . 3^{30} + 2^{60} . 3^{29}}{2^{30} . 3^{30} . 2^{25}}$$→$ $\dfrac{2^{60} . 3^{30} + 2^{60} . 3^{29}}{2^{55} . 3^{30} }$$→$ $\dfrac{2^{55} . (2^{5} . 3 + 2^{5})}{2^{55} . 3^{30} }$$→$ $\dfrac{128}{3}$$FbBinhne2k88$ Bình luận
`{4^30. 27^10+8^20. 3^29}/{6^30. 2^25}`
`={(2^2)^30. (3^3)^10+(2^3)^20. 3^29}/{(2.3)^30. 2^25}`
`={2^60. 3^30+2^60. 3^29}/{2^30. 3^30. 2^25}`
`={2^60. 3^30+2^60. 3^29}/{2^55. 3^30}`
`={2^55. 3^29(2^5. 3+2^5)}/{2^55. 3^29. 3}`
`={2^55. 3^29. 128}/{2^55. 3^29. 3}`
`=128/3`
Đáp án:
$\dfrac{128}{3}$
Giải thích các bước giải:
$($ $4^{30}$ $.$ $27^{10}$ $+$ $8^{20}$ $.$ $3^{29}$ $)$ $:$ $($ $6^{30}$ $.$ $2^{25}$ $)$
$→$ $\dfrac{4^{30} . 27^{10} + 8^{20} . 3^{29}}{6^{30} . 2^{25}}$
$→$ $\dfrac{(2^{2})^{30} . (3^{3})^{10} + (2^{3})^{20} . 3^{29}}{(2.3)^{30} . 2^{25}}$
$→$ $\dfrac{2^{60} . 3^{30} + 2^{60} . 3^{29}}{2^{30} . 3^{30} . 2^{25}}$
$→$ $\dfrac{2^{60} . 3^{30} + 2^{60} . 3^{29}}{2^{55} . 3^{30} }$
$→$ $\dfrac{2^{55} . (2^{5} . 3 + 2^{5})}{2^{55} . 3^{30} }$
$→$ $\dfrac{128}{3}$
$FbBinhne2k88$