rút gọn biểu thức :A=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1) 27/09/2021 Bởi Reagan rút gọn biểu thức :A=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
Đáp án: Giải thích các bước giải: A=(2+1)($2^{2}$ +1)($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1) =(2-1)(2+1)($2^{2}$ +1)($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1) = ($2^{2}$ -1)($2^{2}$+1)($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1) = ($2^{4}$ -1) ($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1) =($2^{8}$ – 1)($2^{8}$ + 1)($2^{16}$ +1)($2^{32}$ +1) =($2^{16}$ – 1)($2^{16}$ +1)($2^{32}$ +1) = ($2^{32}$ – 1)($2^{32}$ + 1) = $2^{64}$ – 1 Vậy A = $2^{64}$ – 1 Bình luận
Đáp án:
Giải thích các bước giải:
A=(2+1)($2^{2}$ +1)($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1)
=(2-1)(2+1)($2^{2}$ +1)($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1)
= ($2^{2}$ -1)($2^{2}$+1)($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1)
= ($2^{4}$ -1) ($2^{4}$ +1)($2^{8}$ +1)($2^{16}$ +1)($2^{32}$ +1)
=($2^{8}$ – 1)($2^{8}$ + 1)($2^{16}$ +1)($2^{32}$ +1)
=($2^{16}$ – 1)($2^{16}$ +1)($2^{32}$ +1)
= ($2^{32}$ – 1)($2^{32}$ + 1)
= $2^{64}$ – 1
Vậy A = $2^{64}$ – 1
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