RÚT GỌN BIỂU THỨC SAU B= (A+3B). ( C – D ) – ( 3A – D ) . ( B+ C ) – 2C ( B-A ) + 2B ( A+ D) 04/09/2021 Bởi Aaliyah RÚT GỌN BIỂU THỨC SAU B= (A+3B). ( C – D ) – ( 3A – D ) . ( B+ C ) – 2C ( B-A ) + 2B ( A+ D)
Đáp án + Giải thích các bước giải: $\rm B = ( A + 3B ) . ( C – D ) – ( 3A – D ) . ( B + C ) – 2C . ( B – A ) + 2B . ( A + D ) \\= AC – AD + 3BC – 3BD – ( 3AB + 3AC – DB – DC ) – 2CB + 2CA + 2BA + 2BD \\= AC – AD + 3BC – 3BD – 3AB – 3AC + DB + DC – 2CB + 2CA + 2BA + 2BD \\= ( AC – 3AC + 2CA ) + ( 2BA – 3AB ) + ( 3BC – 2CB ) + ( 2CA – 3AC ) + ( DB + 2DB – 3BD ) – AD \\= -AB + BC – AC – AD$ Bình luận
B = ( A + 3B ) ( C – D ) – ( 3A – D ) ( B+ C) – 2C ( B – A ) + 2B ( A+ D ) = AC – AD + 3BC – 3BD – 3 AB – 3AC + DB + CD – 2CB + 2AC + 2AB + 2BD = BC – AD – AB + CD = ( BC + CD ) – ( AB + AD ) = C ( B + D ) – A ( B + D ) = ( C – A ) ( B + D ) CHÚC BN HC TỐT Ạ XIN CTLHN Bình luận
Đáp án + Giải thích các bước giải:
$\rm B = ( A + 3B ) . ( C – D ) – ( 3A – D ) . ( B + C ) – 2C . ( B – A ) + 2B . ( A + D ) \\= AC – AD + 3BC – 3BD – ( 3AB + 3AC – DB – DC ) – 2CB + 2CA + 2BA + 2BD \\= AC – AD + 3BC – 3BD – 3AB – 3AC + DB + DC – 2CB + 2CA + 2BA + 2BD \\= ( AC – 3AC + 2CA ) + ( 2BA – 3AB ) + ( 3BC – 2CB ) + ( 2CA – 3AC ) + ( DB + 2DB – 3BD ) – AD \\= -AB + BC – AC – AD$
B = ( A + 3B ) ( C – D ) – ( 3A – D ) ( B+ C) – 2C ( B – A ) + 2B ( A+ D )
= AC – AD + 3BC – 3BD – 3 AB – 3AC + DB + CD – 2CB + 2AC + 2AB + 2BD
= BC – AD – AB + CD = ( BC + CD ) – ( AB + AD )
= C ( B + D ) – A ( B + D ) = ( C – A ) ( B + D )
CHÚC BN HC TỐT Ạ XIN CTLHN