Rút gọn: $\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\left(2^{32}+1\right)-2^{64}$

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1. Đáp án:

   $(2+1).(2^{2}+1).(2^{4}+1).(2^{8}+1).(2^{16}+1).(2^{32}+1)-2^{64}$

   $=(2-1)(2+1).(2^{2}+1).(2^{4}+1).(2^{8}+1).(2^{16}+1).(2^{32}+1)-2^{64}$

   $=(2^2-1).(2^{2}+1).(2^{4}+1).(2^{8}+1).(2^{16}+1).(2^{32}+1)-2^{64}$

   $=(2^4-1).(2^{4}+1).(2^{8}+1).(2^{16}+1).(2^{32}+1)-2^{64}$

   $=(2^8-1).(2^{8}+1).(2^{16}+1).(2^{32}+1)-2^{64}$

   $=(2^{16}-1).(2^{16}+1).(2^{32}+1)-2^{64}$

   $=(2^{32}-1).(2^{32}+1)-2^{64}$ $=(2^{64}-1)-2^{64}$

   $=2^{64}-1-2^{64}$

   $=-1$

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2. Đáp án:

    

   Giải thích các bước giải:

    

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