Rút gọn P=A:B A= $\frac{x-1}{căn x-1}$ – $\frac{(x.căn x) +1}{x-1}$ B= $\frac{x}{căn x-1}$ 14/07/2021 Bởi Emery Rút gọn P=A:B A= $\frac{x-1}{căn x-1}$ – $\frac{(x.căn x) +1}{x-1}$ B= $\frac{x}{căn x-1}$
$A=\dfrac{x-1}{\sqrt[]{x}-1}-\dfrac{x\sqrt[]{x}+1}{x-1}$ $=\dfrac{(\sqrt[]{x}-1)(\sqrt[]{x}+1)}{\sqrt[]{x}-1}-\dfrac{(\sqrt[]{x}+1)(x-\sqrt[]{x}+1)}{(\sqrt[]{x}-1)(\sqrt[]{x}+1)}$ $=\sqrt[]{x}+1-\dfrac{x-\sqrt[]{x}+1}{\sqrt[]{x}-1}$ $=\dfrac{(\sqrt[]{x}+1)(\sqrt[]{x}-1)-x+\sqrt[]{x}-1}{\sqrt[]{x}-1}$ $=\dfrac{x-1-x+\sqrt[]{x}-1}{\sqrt[]{x}-1}$ $=\dfrac{\sqrt[]{x}-2}{\sqrt[]{x}-1}$ $P=A:B$ $=\dfrac{\sqrt[]{x}-2}{\sqrt[]{x}-1}.\dfrac{\sqrt[]{x}-1}{x}$ $=\dfrac{\sqrt[]{x}-2}{x}$ ($x>0$) Bình luận
$A=\dfrac{x-1}{\sqrt[]{x}-1}-\dfrac{x\sqrt[]{x}+1}{x-1}$
$=\dfrac{(\sqrt[]{x}-1)(\sqrt[]{x}+1)}{\sqrt[]{x}-1}-\dfrac{(\sqrt[]{x}+1)(x-\sqrt[]{x}+1)}{(\sqrt[]{x}-1)(\sqrt[]{x}+1)}$
$=\sqrt[]{x}+1-\dfrac{x-\sqrt[]{x}+1}{\sqrt[]{x}-1}$
$=\dfrac{(\sqrt[]{x}+1)(\sqrt[]{x}-1)-x+\sqrt[]{x}-1}{\sqrt[]{x}-1}$
$=\dfrac{x-1-x+\sqrt[]{x}-1}{\sqrt[]{x}-1}$
$=\dfrac{\sqrt[]{x}-2}{\sqrt[]{x}-1}$
$P=A:B$
$=\dfrac{\sqrt[]{x}-2}{\sqrt[]{x}-1}.\dfrac{\sqrt[]{x}-1}{x}$
$=\dfrac{\sqrt[]{x}-2}{x}$ ($x>0$)