Đáp án: \(\left[ \begin{array}{l}x=-1\\x=\frac{-1}{3}\end{array} \right.\) Giải thích các bước giải: $3x^2+4x+1=0$ $⇒(3x^2+3x)+(x+1)=0$ $⇒3x(x+1)+(x+1)=0$ $⇒(x+1)(3x+1)=0$ $⇒$\(\left[ \begin{array}{l}x=-1\\x=\frac{-1}{3}\end{array} \right.\) Vậy \(\left[ \begin{array}{l}x=-1\\x=\frac{-1}{3}\end{array} \right.\) Bình luận
`3x²+4x+1=0` `⇒ 3x²+3x+x+1=0` `⇒ 3x(x+1)+(x+1)=0` `⇒ (3x+1)(x+1)=0` `⇒` \(\left[ \begin{array}{l}3x+1=0⇒3x=-1⇒x=-1/3\\x+1=0⇒x=-1\end{array} \right.\) Bình luận
Đáp án:
\(\left[ \begin{array}{l}x=-1\\x=\frac{-1}{3}\end{array} \right.\)
Giải thích các bước giải:
$3x^2+4x+1=0$
$⇒(3x^2+3x)+(x+1)=0$
$⇒3x(x+1)+(x+1)=0$
$⇒(x+1)(3x+1)=0$
$⇒$\(\left[ \begin{array}{l}x=-1\\x=\frac{-1}{3}\end{array} \right.\)
Vậy \(\left[ \begin{array}{l}x=-1\\x=\frac{-1}{3}\end{array} \right.\)
`3x²+4x+1=0`
`⇒ 3x²+3x+x+1=0`
`⇒ 3x(x+1)+(x+1)=0`
`⇒ (3x+1)(x+1)=0`
`⇒` \(\left[ \begin{array}{l}3x+1=0⇒3x=-1⇒x=-1/3\\x+1=0⇒x=-1\end{array} \right.\)