Tìm x: /x-3/+/x-5/=4 Giúp mk vs nha.mk hứa vote 5* 26/08/2021 Bởi Parker Tìm x: /x-3/+/x-5/=4 Giúp mk vs nha.mk hứa vote 5*
Đáp án: \(\left[ \begin{array}{l}x = 6\\x = 2\end{array} \right.\) Giải thích các bước giải: \(\begin{array}{l}\left| {x – 3} \right| + \left| {x – 5} \right| = 4\\ \to \left[ \begin{array}{l}x – 3 + x – 5 = 4\left( {DK:x \ge 5} \right)\\x – 3 – x + 5 = 4\left( {DK:5 > x \ge 3} \right)\\ – x + 3 – x + 5 = 4\left( {DK:x < 3} \right)\end{array} \right.\\ \to \left[ \begin{array}{l}2x = 12\\2 = 4\left( l \right)\\ – 2x = – 4\end{array} \right.\\ \to \left[ \begin{array}{l}x = 6\\x = 2\end{array} \right.\left( {TM} \right)\end{array}\) Bình luận
Đáp án:
\(\left[ \begin{array}{l}
x = 6\\
x = 2
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
\left| {x – 3} \right| + \left| {x – 5} \right| = 4\\
\to \left[ \begin{array}{l}
x – 3 + x – 5 = 4\left( {DK:x \ge 5} \right)\\
x – 3 – x + 5 = 4\left( {DK:5 > x \ge 3} \right)\\
– x + 3 – x + 5 = 4\left( {DK:x < 3} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
2x = 12\\
2 = 4\left( l \right)\\
– 2x = – 4
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 6\\
x = 2
\end{array} \right.\left( {TM} \right)
\end{array}\)