Tìm x a, 1/5 – x = 5/6 – 1/4 b, 1/10 – (x – 3/25) = 1/50 14/09/2021 Bởi Eden Tìm x a, 1/5 – x = 5/6 – 1/4 b, 1/10 – (x – 3/25) = 1/50
a, $\frac{1}{5}$ – x= $\frac{5}{6}$- $\frac{1}{4}$ ⇔$\frac{1}{5}$ – x= $\frac{7}{12}$ ⇔ x = $\frac{1}{5}$ – $\frac{7}{12}$ ⇔ x = $\frac{-23}{60}$ Vậy x = $\frac{-23}{60}$ b, $\frac{1}{10}$ – (x-$\frac{3}{25}$)=$\frac{1}{5}$ ⇔x-$\frac{3}{25}$ =$\frac{1}{10}$ – $\frac{1}{5}$ ⇔x-$\frac{3}{25}$ =$\frac{2}{25}$ ⇔ x= $\frac{2}{25}$ +$\frac{3}{25}$ ⇔ x =$\frac{1}{5}$ Vậy x =$\frac{1}{5}$ Bình luận
a) 1/5 – x = 5/6 – 1/4 1/5 – x = 7/12 x = -23/60 Vậy x = -23/60 b) 1/10 – (x – 3/25) = 1/50 x – 3/25 = 2/25 x = 1/5 Vậy x = 1/5 Xin ctlhn Bình luận
a, $\frac{1}{5}$ – x= $\frac{5}{6}$- $\frac{1}{4}$
⇔$\frac{1}{5}$ – x= $\frac{7}{12}$
⇔ x = $\frac{1}{5}$ – $\frac{7}{12}$
⇔ x = $\frac{-23}{60}$
Vậy x = $\frac{-23}{60}$
b, $\frac{1}{10}$ – (x-$\frac{3}{25}$)=$\frac{1}{5}$
⇔x-$\frac{3}{25}$ =$\frac{1}{10}$ – $\frac{1}{5}$
⇔x-$\frac{3}{25}$ =$\frac{2}{25}$
⇔ x= $\frac{2}{25}$ +$\frac{3}{25}$
⇔ x =$\frac{1}{5}$
Vậy x =$\frac{1}{5}$
a) 1/5 – x = 5/6 – 1/4
1/5 – x = 7/12
x = -23/60
Vậy x = -23/60
b) 1/10 – (x – 3/25) = 1/50
x – 3/25 = 2/25
x = 1/5
Vậy x = 1/5
Xin ctlhn