tìm x a)-x-2/3=-6/7 b)(x-1)^2=16 c)!x-1/2!-5/6=0 d)x+1/3=2/7-(-1/5) 18/11/2021 Bởi Vivian tìm x a)-x-2/3=-6/7 b)(x-1)^2=16 c)!x-1/2!-5/6=0 d)x+1/3=2/7-(-1/5)
a)x-2= -6 b)(x-1)^2=16 c) x−1⋅1−1⋅ 5=0 d)x+1/3=2/7 3 7 (x-1)^2=4^2 2! 6 x+1/3=2/7+1/5 x=-6–2 ⇒ x-1=4 hoặc x-1=-4 x−1⋅1−1⋅ 5=0 x+1/3=10/35+7/15 7 3 *x-1=4 *x-1=-4 2 6 x+1/3=17/35 x=-18–14 x=4+1 x=(-4)+1 x-1-1.5=0 x=17/35-1/3 21 21 x=5 x=-3 2 6 x= 51/105-35/105 Vậy x ∈ {5;-3} x−1−5=0 x=16/105 21 2 6 x-4-=0 3 x=0+4 3 x=4 3 Bình luận
a, -x – `2/3` = `-6/7` -x = `-6/7` + `2/3` -x = `14/21` – `18/21` -x = `-4/21` x = `4/21` Vậy x = `4/21` b, `( x – 1 )^2` = 16 `=>` \(\left[ \begin{array}{l}(x-1)^2=4^2\\(x-1)^2 = (-4)^2\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x-1=4\\x-1 = -4\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.\) Vậy x ∈ { 5; -3 } c, | x – `1/2` | – `5/6` = 0 | x – `1/2` | = `5/6` `=>` \(\left[ \begin{array}{l}x-\frac{1}{2} = \frac{5}{6}\\x-\frac{1}{2}=\frac{-5}{6} \end{array} \right.\) `=>` ( bạn tự tính tiếp ạ ) d, x + `1/3` = `2/7` – ( -`1/5` ) x + `1/3` = `2/7` + `1/5` x + `1/3` = `17/10` x = `17/10` – `1/3` x = `51/30` – `10/30` x = `41/30` Vậy x = `41/30` Bình luận
a)x-2= -6 b)(x-1)^2=16 c) x−1⋅1−1⋅ 5=0 d)x+1/3=2/7
3 7 (x-1)^2=4^2 2! 6 x+1/3=2/7+1/5
x=-6–2 ⇒ x-1=4 hoặc x-1=-4 x−1⋅1−1⋅ 5=0 x+1/3=10/35+7/15
7 3 *x-1=4 *x-1=-4 2 6 x+1/3=17/35
x=-18–14 x=4+1 x=(-4)+1 x-1-1.5=0 x=17/35-1/3
21 21 x=5 x=-3 2 6 x= 51/105-35/105 Vậy x ∈ {5;-3} x−1−5=0 x=16/105
21 2 6
x-4-=0
3
x=0+4
3
x=4
3
a, -x – `2/3` = `-6/7`
-x = `-6/7` + `2/3`
-x = `14/21` – `18/21`
-x = `-4/21`
x = `4/21`
Vậy x = `4/21`
b, `( x – 1 )^2` = 16
`=>` \(\left[ \begin{array}{l}(x-1)^2=4^2\\(x-1)^2 = (-4)^2\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x-1=4\\x-1 = -4\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.\)
Vậy x ∈ { 5; -3 }
c, | x – `1/2` | – `5/6` = 0
| x – `1/2` | = `5/6`
`=>` \(\left[ \begin{array}{l}x-\frac{1}{2} = \frac{5}{6}\\x-\frac{1}{2}=\frac{-5}{6} \end{array} \right.\)
`=>` ( bạn tự tính tiếp ạ )
d, x + `1/3` = `2/7` – ( -`1/5` )
x + `1/3` = `2/7` + `1/5`
x + `1/3` = `17/10`
x = `17/10` – `1/3`
x = `51/30` – `10/30`
x = `41/30`
Vậy x = `41/30`