tìm x a) (2/5-x)^3=-8/27 b)4/3:x=3/4:2/5 c) 1/2x:8/7=0,03:4/11

tìm x
a) (2/5-x)^3=-8/27
b)4/3:x=3/4:2/5
c) 1/2x:8/7=0,03:4/11

0 bình luận về “tìm x a) (2/5-x)^3=-8/27 b)4/3:x=3/4:2/5 c) 1/2x:8/7=0,03:4/11”

  1. Đáp án:

    `a)`

    ` (2/5 -x)^3 = (-8/27) = (-2/3)^3`

    ` => 2/5 – x = -2/3`

    ` => x= 2/5 +2/3`

    ` => x= 16/15`

    `b)`

    ` 4/3 : x = 3/4 : 2/5`

    ` 4/3 : x =15/8`

    ` x =4/3 : 15/8`

    ` x  =32/45`

    `c)`

    ` 1/(2) *x : 8/7 = 0,03 * 4/11`

    `=> 1/(2) *x : 8/7 = 3/275`

    ` 1/(2) x = 24/1925`

    ` x = 48/1925`

    Bình luận
  2. Bạn tham khảo!
    $a)$ $($ $\dfrac{2}{5}$ $-$ $x$ $)$³ $=$ $\dfrac{-8}{27}$
    $→$ $($ $\dfrac{2}{5}$ $-$ $x$ $)$³ $=$ $($ $\dfrac{2}{3}$ $)$³ và $($ $\dfrac{2}{5}$ $-$ $x$ $)$³ $=$ $($ $\dfrac{-2}{3}$ $)$³
    $→$ $\dfrac{2}{5}$ $-$ $x$ $=$ $\dfrac{2}{3}$ và $\dfrac{2}{5}$ $-$ $x$ $=$ $\dfrac{-2}{3}$
    $→$ $x$ $=$ $\dfrac{2}{5}$ $-$ $\dfrac{2}{3}$ và $x$ $=$ $\dfrac{2}{5}$ $-$ $\dfrac{-2}{3}$
    $→$ $x$ $=$ $\dfrac{-4}{15}$ và $x$ $=$ $\dfrac{16}{15}$
    $b)$ $\dfrac{4}{3}$ $:$ $x$ $=$ $\dfrac{3}{4}$ $:$ $\dfrac{2}{5}$
    $→$ $\dfrac{4}{3}$ $:$ $x$ $=$ $\dfrac{15}{8}$
    $→$ $x$ $=$ $\dfrac{4}{3}$ $:$ $\dfrac{15}{8}$
    $→$ $x$ $=$ $\dfrac{32}{45}$
    $c)$ $\dfrac{1}{2}$ $.$ $x$ $:$ $\dfrac{8}{7}$ $=$ $0.03$ $:$ $\dfrac{4}{11}$
    $→$ $\dfrac{1}{2}$ $.$ $x$ $:$ $\dfrac{8}{7}$ $=$ $\dfrac{3}{275}$
    $→$ $\dfrac{1}{2}$ $.$ $x$ $=$ $\dfrac{3}{275}$ $.$ $\dfrac{8}{7}$
    $→$ $\dfrac{1}{2}$ $.$ $x$ $=$ $\dfrac{24}{1925}$
    $→$ $x$ $=$ $\dfrac{24}{1925}$ $:$ $\dfrac{1}{2}$
    $→$ $x$ $=$ $\dfrac{12}{1925}$
    $FbBinhne2k88$

     

    Bình luận

Viết một bình luận