Tìm x a)5^x.5^3=125^2.25^3 b)(-1/4)^x-2=1/64 c) (x-3/4)^2=49/81 06/07/2021 Bởi Brielle Tìm x a)5^x.5^3=125^2.25^3 b)(-1/4)^x-2=1/64 c) (x-3/4)^2=49/81
Đáp án: `a)` ` 5^(x) * 5^3 = 125^2 * 25^3` ` => 5^(x) * 5^3 = (5^3)^2 * (5^2)^3` ` => 5^(x+3) = 5^6 * 5^6 = 5^12` ` => x +3 = 12` ` => x= 9` `b)` ` (-1/4)^(x-2) = 1/64 = (-1/4)^4` ` => x-2 = 4` ` => x= 6` `c)` ` (x-3/4)^2 = 49/81 = (7/9)^2 = -7/9` TH1 ` x-3/4 = 7/9` ` => x= 7/9 +3/4 = 55/36` TH2 ` x-3/4 = -7/9` ` => x= -7/9 +3/4` ` => x= -1/36` Vậy ` x= 55/36` hoặc ` x=-1/36` Bình luận
Đáp án: a) $5^{x}$ . $5^{3}$ = $125^{2}$ . $25^{3}$ $5^{x}$ . $5^{3}$ = 244140625 = $5^{12}$ x = $5^{12}$ : $5^{3}$ = $5^{12 – 3}$ = $5^{4}$ x = 4 Bình luận
Đáp án:
`a)`
` 5^(x) * 5^3 = 125^2 * 25^3`
` => 5^(x) * 5^3 = (5^3)^2 * (5^2)^3`
` => 5^(x+3) = 5^6 * 5^6 = 5^12`
` => x +3 = 12`
` => x= 9`
`b)`
` (-1/4)^(x-2) = 1/64 = (-1/4)^4`
` => x-2 = 4`
` => x= 6`
`c)`
` (x-3/4)^2 = 49/81 = (7/9)^2 = -7/9`
TH1
` x-3/4 = 7/9`
` => x= 7/9 +3/4 = 55/36`
TH2
` x-3/4 = -7/9`
` => x= -7/9 +3/4`
` => x= -1/36`
Vậy ` x= 55/36` hoặc ` x=-1/36`
Đáp án:
a) $5^{x}$ . $5^{3}$ = $125^{2}$ . $25^{3}$
$5^{x}$ . $5^{3}$ = 244140625 = $5^{12}$
x = $5^{12}$ : $5^{3}$ = $5^{12 – 3}$ = $5^{4}$
x = 4