Tìm x a, 71 – ( 33 + x ) = 26 b, 45 – ( x + 9 ) = 6 c, 2x – 49 = 5 × 3^2 18/08/2021 Bởi Sadie Tìm x a, 71 – ( 33 + x ) = 26 b, 45 – ( x + 9 ) = 6 c, 2x – 49 = 5 × 3^2
$a,$ `71 – ( 33 + x ) = 26` `⇔ 33+x = 45` `⇔ x = 12` Vậy `x=12` $b$, `45 – ( x + 9 ) = 6` `⇔ x + 9 = 39` `⇔ x = 30` Vậy $x=30$ $c$) `2x – 49 = 5. 3^2` `⇔ 2x – 49 =45` `⇔ 2x =94` `⇔ x = 47` Vậy `x=47` Bình luận
a, 71 – (33 + `x`) = 26 33 + `x` = 71 – 26 33 + `x` = 45 `x` = 45 – 33 `x` = 12 b, 45 – (`x` + 9) = 6 `x` + 9 = 45 – 6 `x` + 9 = 39 `x` = 39 – 9 `x` = 30 c, 2`x` – 49 = 5 × 3² 2`x` – 49 = 45 2`x` = 45 + 49 2`x` = 94 `x` = 94 : 2 `x` = 47 Bình luận
$a,$ `71 – ( 33 + x ) = 26`
`⇔ 33+x = 45`
`⇔ x = 12`
Vậy `x=12`
$b$, `45 – ( x + 9 ) = 6`
`⇔ x + 9 = 39`
`⇔ x = 30`
Vậy $x=30$
$c$) `2x – 49 = 5. 3^2`
`⇔ 2x – 49 =45`
`⇔ 2x =94`
`⇔ x = 47`
Vậy `x=47`
a, 71 – (33 + `x`) = 26
33 + `x` = 71 – 26
33 + `x` = 45
`x` = 45 – 33
`x` = 12
b, 45 – (`x` + 9) = 6
`x` + 9 = 45 – 6
`x` + 9 = 39
`x` = 39 – 9
`x` = 30
c, 2`x` – 49 = 5 × 3²
2`x` – 49 = 45
2`x` = 45 + 49
2`x` = 94
`x` = 94 : 2
`x` = 47