tìm x biết |x|=0 |x|=1,375 |x|= $\frac{1}{5}$ |x|= 3$\frac{1}{4}$ |x -1,5|=2 |x+ $\frac{3}{4}$|- $\frac{1}{2}$=0 01/08/2021 Bởi Ivy tìm x biết |x|=0 |x|=1,375 |x|= $\frac{1}{5}$ |x|= 3$\frac{1}{4}$ |x -1,5|=2 |x+ $\frac{3}{4}$|- $\frac{1}{2}$=0
Đáp án: ` |x| = 0` ` => x =0` ********* ` |x| = 1,375` ` =>` \(\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\) ********* ` |x| = 1/5` ` => ` \(\left[ \begin{array}{l}x=\dfrac{1}{5}\\x=\dfrac{-1}{5}\end{array} \right.\) ********* ` |x| = 3 1/4` ` => |x| = 13/4` ` =>` \(\left[ \begin{array}{l}x=\dfrac{13}{4}\\x=\dfrac{-13}{4}\end{array} \right.\) ********* ` |x -1,5| = 2` Trường hợp `1` ` x -1,5 = 2` ` => x= 2+1,5 = 3,5` TH`2` ` x -1,5 = -2` ` x =-2 +1,5` ` x = -0,5` ********* `| x +3/4| -1/2 = 0` ` |x+3/4| = 1/2` TH1 ` x +3/4 = 1/2` ` x = 1/2 – 3/4` `x = -1/4` TH2 ` x + 3/4 = -1/2` ` x = -1/2 – 3/4` ` x =-5/4` Bình luận
Đáp án: Giải thích các bước giải: + ) |x| = 0 → x = 0 + ) |x| = 1,375 → \(\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\) + ) |x| = $\frac{1}{5}$ → \(\left[ \begin{array}{l}x=\frac{1}{5}\\x=-\frac{1}{5}\end{array} \right.\) + ) |x| = 3$\frac{1}{4}$ → \(\left[ \begin{array}{l}x = 3\frac{1}{4} \\x=-(3\frac{1}{4}) \end{array} \right.\) + ) | x – 1,5 | = 2 → \(\left[ \begin{array}{l}x -1,5=2\\x-1,5=-2 \end{array} \right.\) → \(\left[ \begin{array}{l}x =3,5\\x=-0,5\end{array} \right.\) + ) | x + $\frac{3}{4}$ | – $\frac{1}{2}$ = 0 | x + $\frac{3}{4}$ | = $\frac{1}{2}$ → \(\left[ \begin{array}{l}x + \frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{array} \right.\) → \(\left[ \begin{array}{l}x =-\frac{1}{4}\\x=-\frac{5}{4}\end{array} \right.\) Bình luận
Đáp án:
` |x| = 0`
` => x =0`
*********
` |x| = 1,375`
` =>`
\(\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\)
*********
` |x| = 1/5`
` => `
\(\left[ \begin{array}{l}x=\dfrac{1}{5}\\x=\dfrac{-1}{5}\end{array} \right.\)
*********
` |x| = 3 1/4`
` => |x| = 13/4`
` =>`
\(\left[ \begin{array}{l}x=\dfrac{13}{4}\\x=\dfrac{-13}{4}\end{array} \right.\)
*********
` |x -1,5| = 2`
Trường hợp `1`
` x -1,5 = 2`
` => x= 2+1,5 = 3,5`
TH`2`
` x -1,5 = -2`
` x =-2 +1,5`
` x = -0,5`
*********
`| x +3/4| -1/2 = 0`
` |x+3/4| = 1/2`
TH1
` x +3/4 = 1/2`
` x = 1/2 – 3/4`
`x = -1/4`
TH2
` x + 3/4 = -1/2`
` x = -1/2 – 3/4`
` x =-5/4`
Đáp án:
Giải thích các bước giải:
+ ) |x| = 0
→ x = 0
+ ) |x| = 1,375
→ \(\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\)
+ ) |x| = $\frac{1}{5}$
→ \(\left[ \begin{array}{l}x=\frac{1}{5}\\x=-\frac{1}{5}\end{array} \right.\)
+ ) |x| = 3$\frac{1}{4}$
→ \(\left[ \begin{array}{l}x = 3\frac{1}{4} \\x=-(3\frac{1}{4}) \end{array} \right.\)
+ ) | x – 1,5 | = 2
→ \(\left[ \begin{array}{l}x -1,5=2\\x-1,5=-2 \end{array} \right.\)
→ \(\left[ \begin{array}{l}x =3,5\\x=-0,5\end{array} \right.\)
+ ) | x + $\frac{3}{4}$ | – $\frac{1}{2}$ = 0
| x + $\frac{3}{4}$ | = $\frac{1}{2}$
→ \(\left[ \begin{array}{l}x + \frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{array} \right.\)
→ \(\left[ \begin{array}{l}x =-\frac{1}{4}\\x=-\frac{5}{4}\end{array} \right.\)