Tìm x biết x-1/2019+x-2/2018=x-3/2017+x-4/2016 CẢM ƠN Ạ 17/07/2021 Bởi Genesis Tìm x biết x-1/2019+x-2/2018=x-3/2017+x-4/2016 CẢM ƠN Ạ
x-1/2019+x-2/2018=x-3/2017+x-4/2016 ⇒(x-1/2019-1)+(x-2/2018-1)=(x-3/2017-1)+(x-4/2016-1) ⇒x+2020/2019+x-2020/2018-x-2020/2017+x-2020/2016=0 ⇒(x-2020)(1/2019+1/2018-1/2017+1/2016)=0 ⇒x-2020=0 ⇒x=2020 Xin ctlhn ak Bình luận
Đáp án + Giải thích các bước giải: `(x-1)/(2019)+(x-2)/(2018)=(x-3)/(2017)+(x-4)/(2016)` `->((x-1)/(2019)-1)+((x-2)/(2018)-1)=((x-3)/(2017)-1)+((x-4)/(2016)-1)` `->((x-1)/(2019)-(2019)/(2019))+((x-2)/(2018)-(2018)/(2018))=((x-3)/(2017)-(2017)/(2017))+((x-4)/(2016)-(2016)/(2016))` `->(x-2020)/(2019)+(x-2020)/(2018)=(x-2020)/(2017)+(x-2020)/(2016)` `->(x-2020)/(2019)+(x-2020)/(2018)-(x-2020)/(2017)-(x-2020)/(2016)=0` `->(x-2020)((1)/(2019)+(1)/(2018)-(1)/(2017)-(1)/(2016))=0` `->x-2020=0` . Vì `(1)/(2019)+(1)/(2018)-(1)/(2017)-(1)/(2016)\ne0` `->x=2020` Bình luận
x-1/2019+x-2/2018=x-3/2017+x-4/2016
⇒(x-1/2019-1)+(x-2/2018-1)=(x-3/2017-1)+(x-4/2016-1)
⇒x+2020/2019+x-2020/2018-x-2020/2017+x-2020/2016=0
⇒(x-2020)(1/2019+1/2018-1/2017+1/2016)=0
⇒x-2020=0
⇒x=2020
Xin ctlhn ak
Đáp án + Giải thích các bước giải:
`(x-1)/(2019)+(x-2)/(2018)=(x-3)/(2017)+(x-4)/(2016)`
`->((x-1)/(2019)-1)+((x-2)/(2018)-1)=((x-3)/(2017)-1)+((x-4)/(2016)-1)`
`->((x-1)/(2019)-(2019)/(2019))+((x-2)/(2018)-(2018)/(2018))=((x-3)/(2017)-(2017)/(2017))+((x-4)/(2016)-(2016)/(2016))`
`->(x-2020)/(2019)+(x-2020)/(2018)=(x-2020)/(2017)+(x-2020)/(2016)`
`->(x-2020)/(2019)+(x-2020)/(2018)-(x-2020)/(2017)-(x-2020)/(2016)=0`
`->(x-2020)((1)/(2019)+(1)/(2018)-(1)/(2017)-(1)/(2016))=0`
`->x-2020=0` . Vì `(1)/(2019)+(1)/(2018)-(1)/(2017)-(1)/(2016)\ne0`
`->x=2020`