tìm x,|x| biết x=-3 1/5 |1/5 – x|=4 1/2 |2x + 1|-5=2 27/07/2021 Bởi Harper tìm x,|x| biết x=-3 1/5 |1/5 – x|=4 1/2 |2x + 1|-5=2
`x=-3 1/5` `=> x=-16/5` `|1/5 – x|=4 1/2` `=> |1/5-x|=9/2` `=>` \(\left[ \begin{array}{l}1/5-x=9/2\\1/5-x=-9/2\end{array} \right.\) `=> x=` \(\left[ \begin{array}{l}x=-4.3\\x=4,7\end{array} \right.\) `|2x + 1|-5=2` `=> |2x+1|=2+5=7` `=>` \(\left[ \begin{array}{l}2x+1=7\\2x+1=-7\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=3\\x=-4\end{array} \right.\) Bình luận
`|1/5 – x|=4 1/2` => |1/5-x|=9/2 => \(\left[ \begin{array}{l}1/5-x=9/2\\1/5-x=-9/2\end{array} \right.\) => x= \(\left[ \begin{array}{l}x=-4.3\\x=4,7\end{array} \right.\) |2x + 1|-5=2 => |2x+1|=2+5=7 => \(\left[ \begin{array}{l}2x+1=7\\2x+1=-7\end{array} \right.\) => \(\left[ \begin{array}{l}x=3\\x=-4\end{array} \right.\) Bình luận
`x=-3 1/5`
`=> x=-16/5`
`|1/5 – x|=4 1/2`
`=> |1/5-x|=9/2`
`=>` \(\left[ \begin{array}{l}1/5-x=9/2\\1/5-x=-9/2\end{array} \right.\)
`=> x=` \(\left[ \begin{array}{l}x=-4.3\\x=4,7\end{array} \right.\)
`|2x + 1|-5=2`
`=> |2x+1|=2+5=7`
`=>` \(\left[ \begin{array}{l}2x+1=7\\2x+1=-7\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=3\\x=-4\end{array} \right.\)
`|1/5 – x|=4 1/2`
=> |1/5-x|=9/2
=> \(\left[ \begin{array}{l}1/5-x=9/2\\1/5-x=-9/2\end{array} \right.\)
=> x= \(\left[ \begin{array}{l}x=-4.3\\x=4,7\end{array} \right.\)
|2x + 1|-5=2
=> |2x+1|=2+5=7
=> \(\left[ \begin{array}{l}2x+1=7\\2x+1=-7\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=3\\x=-4\end{array} \right.\)