Tìm x, biết: 3/2- |1+2x|=1/5 Mong mn giúp ạ! 26/11/2021 Bởi Jasmine Tìm x, biết: 3/2- |1+2x|=1/5 Mong mn giúp ạ!
Giải thích các bước giải: `3/2- |1+2x|=1/5``=>|1+2x|=3/2-1/5``=>|1+2x|=13/10``=>`\(\left[ \begin{array}{l}1+2x=\dfrac{13}{10}\\1+2x=\dfrac{-13}{10}\end{array} \right.\) `=>`\(\left[ \begin{array}{l}2x=\dfrac{13}{10}-1\\x=\dfrac{-13}{10}-1\end{array} \right.\) `=>`\(\left[ \begin{array}{l}2x=\dfrac{3}{10}\\x=\dfrac{-23}{10}\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=\dfrac{3}{20}\\x=\dfrac{-23}{20}\end{array} \right.\) Bình luận
Giải thích các bước giải:
`3/2- |1+2x|=1/5`
`=>|1+2x|=3/2-1/5`
`=>|1+2x|=13/10`
`=>`\(\left[ \begin{array}{l}1+2x=\dfrac{13}{10}\\1+2x=\dfrac{-13}{10}\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=\dfrac{13}{10}-1\\x=\dfrac{-13}{10}-1\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}2x=\dfrac{3}{10}\\x=\dfrac{-23}{10}\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=\dfrac{3}{20}\\x=\dfrac{-23}{20}\end{array} \right.\)