Toán tìm x biết x-3/4=13/10 :26/5 b)|x-2|-1=0 29/11/2021 By Madelyn tìm x biết x-3/4=13/10 :26/5 b)|x-2|-1=0
`a)x-3/4=13/10÷26/5` `→x-3/4=1/4` `→x=1/4+3/4` `→x=1` Vậy `x=1` `b)|x-2|-1=0` `→|x-2|=1` `→` \(\left[ \begin{array}{l}x-2=1\\x-2=-1\end{array} \right.\) `→` \(\left[ \begin{array}{l}x=3\\x=1\end{array} \right.\) Vậy `x∈{3;1}` Trả lời
a) x-3/4=13/10 :26/5 x-3/4=1/4 x = 1/4+3/4 x = 1 b) |x-2|-1=0 ⇒ x-2 =±1 ⇒ x-2=1 hoặc x-3= -1 +) x-2 =1 x=3 +) x-2=-1 x= 1 Vậy x ∈ {1,3} Trả lời
`a)x-3/4=13/10÷26/5`
`→x-3/4=1/4`
`→x=1/4+3/4`
`→x=1`
Vậy `x=1`
`b)|x-2|-1=0`
`→|x-2|=1`
`→` \(\left[ \begin{array}{l}x-2=1\\x-2=-1\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=3\\x=1\end{array} \right.\)
Vậy `x∈{3;1}`
a) x-3/4=13/10 :26/5
x-3/4=1/4
x = 1/4+3/4
x = 1
b) |x-2|-1=0
⇒ x-2 =±1
⇒ x-2=1 hoặc x-3= -1
+) x-2 =1
x=3
+) x-2=-1
x= 1
Vậy x ∈ {1,3}