Tìm x, biết:
a, 17 – x = 7 – 6x
b, -15 + 2x = 5x -21
c, (2x – 4) . 3 = 0
d, 5 . (2x – 1) = -25
e, (2x – 4) . (x + 3) = 0
Tìm x, biết:
a, 17 – x = 7 – 6x
b, -15 + 2x = 5x -21
c, (2x – 4) . 3 = 0
d, 5 . (2x – 1) = -25
e, (2x – 4) . (x + 3) = 0
Đáp án + Giải thích các bước giải:
Ta có :
`a,17-x=7-6x`
`→-x+6x=7-17`
`→5x=-10`
`→x=-2`
`b,-15+2x=5x-21`
`→2x-5x=15-21`
`→-3x=-6`
`→x=2`
`c,(2x-4).3=0`
`→2x-4=0`
`→2x=4`
`→x=2`
`d,5(2x-1)=-25`
`→2x-1=-5`
`→2x=-4`
`→x=-2`
`e,(2x-4)(x+3)=0`
`→2(x-2)(x+3)=0`
`→(x-2)(x+3)=0`
`→` \(\left[ \begin{array}{l}x-2=0\\x+3=0\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=2\\x=-3\end{array} \right.\)
Vậy `x∈{2;-3}`
Đáp án:
Giải thích các bước giải:
a, $17 – x = 7 – 6x$
$-x + 6x = 7 – 17$
$5x = -10$
$x =-2$
b, $-15 + 2x = 5x -21$
$5x – 2x = -15 + 21$
$3x = 6$
$x = 2$
c) $(2x – 4) . 3 = 0$
$2x – 4 = 0$
$2x = 4$
$x = 2$
d, $5 . (2x – 1) = -25$
$2x – 1 = -5$
$2x = -4$
$x = -2$
e,$ (2x – 4) . (x + 3) = 0$
\(\left[ \begin{array}{l}2x – 4=0\\x + 3=0\end{array} \right.\)
\(\left[ \begin{array}{l}x=2\\x=-3\end{array} \right.\)