tìm x biết a 20%+3/2.x=-10 b 11/3.x-1/3=9/4 25/10/2021 Bởi Lyla tìm x biết a 20%+3/2.x=-10 b 11/3.x-1/3=9/4
Bạn tham khảo : a , 20% + $\frac{3}{2}$ . x = (-10) 0 , 02 + $\frac{3}{2}$ . x = (-10) $\frac{3}{2}$ . x = (-10) – 0,02 $\frac{3}{2}$ . x = -10,02 x = -10,02 : $\frac{3}{2}$ x = -6 , 68 b , 11/3.x-1/3=9/4 11/3x = 9/4 + 1/3 11/3 x = 31/12 x = 31/12 : 11/3 x = 31/44 Bình luận
a) 20%+3/2.x=-10 (=) 3/2.x=-10-20%=-10,2 (=) x = -10,2 : 3/2 = -6,8 b) 11/3.x-1/3=9/4 (=) 11/3.x=9/4+1/3 (=) 11/3.x=31/12 (=) x = 31/12 : 11/3 = 31/44 Bình luận
Bạn tham khảo :
a ,
20% + $\frac{3}{2}$ . x = (-10)
0 , 02 + $\frac{3}{2}$ . x = (-10)
$\frac{3}{2}$ . x = (-10) – 0,02
$\frac{3}{2}$ . x = -10,02
x = -10,02 : $\frac{3}{2}$
x = -6 , 68
b ,
11/3.x-1/3=9/4
11/3x = 9/4 + 1/3
11/3 x = 31/12
x = 31/12 : 11/3
x = 31/44
a) 20%+3/2.x=-10
(=) 3/2.x=-10-20%=-10,2
(=) x = -10,2 : 3/2 = -6,8
b) 11/3.x-1/3=9/4
(=) 11/3.x=9/4+1/3
(=) 11/3.x=31/12
(=) x = 31/12 : 11/3 = 31/44