Tìm x, biết A/ `x/5`=`2/3` B/ `x/3`-`1/2`=`1/5` C/ `x/5`+`1/2`=`6/10` 03/09/2021 Bởi Eva Tìm x, biết A/ `x/5`=`2/3` B/ `x/3`-`1/2`=`1/5` C/ `x/5`+`1/2`=`6/10`
`a)` `x/5 = 2/3` `⇔ x = 3,33` (Đúng là 3,333333333) `Vậy x = { 3,33 }` `b)` `x/3 – 1/2 = 1/5` `⇔ x/3 = 1/5 + 1/2` `⇔ x/3 = 7/10` `⇔ x = 2,1` `Vậy x = { 2,1 }` `c)` `x/5 + 1/2 = 6/10` `⇔ x/5 = 6/10 – 1/2` `⇔ x/5 = 1/10` `⇔ x = 0,5` `Vậy x = { 0,5 }` Bình luận
A/$\frac{x}{5}$ = $\frac{2}{3}$ ⇔ 3x = 10 ⇔ x = $\frac{10}{3}$ B/ $\frac{x}{3}$ – $\frac{1}{2}$ = $\frac{1}{5}$ ⇔$\frac{x}{3}$ = $\frac{7}{10}$ ⇔ 10x = 21 ⇔ x = $\frac{21}{10}$ C/ $\frac{x}{5}$ + $\frac{1}{2}$ = $\frac{6}{10}$ ⇔$\frac{x}{5}$ = $\frac{1}{10}$ ⇔ 10x = 5 ⇔ x = $\frac{1}{2}$ $chomikxinctlhnnha$ Bình luận
`a)`
`x/5 = 2/3`
`⇔ x = 3,33` (Đúng là 3,333333333)
`Vậy x = { 3,33 }`
`b)`
`x/3 – 1/2 = 1/5`
`⇔ x/3 = 1/5 + 1/2`
`⇔ x/3 = 7/10`
`⇔ x = 2,1`
`Vậy x = { 2,1 }`
`c)`
`x/5 + 1/2 = 6/10`
`⇔ x/5 = 6/10 – 1/2`
`⇔ x/5 = 1/10`
`⇔ x = 0,5`
`Vậy x = { 0,5 }`
A/$\frac{x}{5}$ = $\frac{2}{3}$
⇔ 3x = 10
⇔ x = $\frac{10}{3}$
B/ $\frac{x}{3}$ – $\frac{1}{2}$ = $\frac{1}{5}$
⇔$\frac{x}{3}$ = $\frac{7}{10}$
⇔ 10x = 21
⇔ x = $\frac{21}{10}$
C/ $\frac{x}{5}$ + $\frac{1}{2}$ = $\frac{6}{10}$
⇔$\frac{x}{5}$ = $\frac{1}{10}$
⇔ 10x = 5
⇔ x = $\frac{1}{2}$
$chomikxinctlhnnha$