tìm x biết a) (5x-3)-(2x+6)=(x+1)-2(x-10) b) tìm x,y,z biết x/2=y/3=z/5 và x+y-2z=10 01/11/2021 Bởi Genesis tìm x biết a) (5x-3)-(2x+6)=(x+1)-2(x-10) b) tìm x,y,z biết x/2=y/3=z/5 và x+y-2z=10
Đáp án: \(\begin{array}{l}x = – 4\\ \to \left\{ \begin{array}{l}y = – 6\\z = – 10\end{array} \right.\end{array}\) Giải thích các bước giải: \(\begin{array}{l}a.5x – 3 – 2x – 6 = x + 1 – 2x + 20\\ \to 4x = 30\\ \to x = \frac{{30}}{4} = \frac{{15}}{2}\\b.\left\{ \begin{array}{l}\frac{x}{2} = \frac{y}{3}\\\frac{x}{2} = \frac{z}{5}\\x + y – 2z = 10\end{array} \right.\\ \to \left\{ \begin{array}{l}\frac{3}{2}x = y\\z = \frac{5}{2}x\\x + \frac{3}{2}x – 2.\frac{5}{2}x = 10\left( * \right)\end{array} \right.\\\left( * \right) \to x + \frac{3}{2}x – 5x = 10\\ \to \left( {1 + \frac{3}{2} – 5} \right)x = 10\\ \to – \frac{5}{2}x = 10\\ \to x = – 4\\ \to \left\{ \begin{array}{l}y = – 6\\z = – 10\end{array} \right.\end{array}\) Bình luận
Đáp án:
\(\begin{array}{l}
x = – 4\\
\to \left\{ \begin{array}{l}
y = – 6\\
z = – 10
\end{array} \right.
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.5x – 3 – 2x – 6 = x + 1 – 2x + 20\\
\to 4x = 30\\
\to x = \frac{{30}}{4} = \frac{{15}}{2}\\
b.\left\{ \begin{array}{l}
\frac{x}{2} = \frac{y}{3}\\
\frac{x}{2} = \frac{z}{5}\\
x + y – 2z = 10
\end{array} \right.\\
\to \left\{ \begin{array}{l}
\frac{3}{2}x = y\\
z = \frac{5}{2}x\\
x + \frac{3}{2}x – 2.\frac{5}{2}x = 10\left( * \right)
\end{array} \right.\\
\left( * \right) \to x + \frac{3}{2}x – 5x = 10\\
\to \left( {1 + \frac{3}{2} – 5} \right)x = 10\\
\to – \frac{5}{2}x = 10\\
\to x = – 4\\
\to \left\{ \begin{array}{l}
y = – 6\\
z = – 10
\end{array} \right.
\end{array}\)