Tìm x , biết : a, ( x – 78 ) . 25 = 0 b, 37 . ( x – 1 ) = 37 c, ( x – 14 ) : 2 = 3 d, ( 30 – x ) . 4 = 92 25/07/2021 Bởi Kennedy Tìm x , biết : a, ( x – 78 ) . 25 = 0 b, 37 . ( x – 1 ) = 37 c, ( x – 14 ) : 2 = 3 d, ( 30 – x ) . 4 = 92
$\text{a, (x – 78) . 25 = 0}$$\text{x – 78 = 0 : 25}$$\text{x – 78 = 0}$$\text{x = 0 + 78}$$\text{x = 78}$ $\text{b, 37 . (x – 1) = 37}$$\text{x – 1 = 37 : 37}$$\text{x – 1 = 1}$$\text{x = 1 + 1}$$\text{x = 2}$ $\text{c, (x – 14) : 2 = 3}$$\text{x – 14 = 3 x 2}$$\text{x – 14 = 6}$$\text{x = 6 + 14}$$\text{x = 20}$ $\text{d, (30 – x) . 4 = 92}$$\text{30 – x = 92 : 4}$$\text{30 – x = 23}$$\text{x = 30 – 23}$$\text{x = 7}$ Bình luận
a) (x – 78) . 25 = 0 x – 78 = 0 : 25 x – 78 = 0 x = 0 + 78 x = 78 b) 37 . (x – 1) = 37 x – 1 = 37 : 37 x – 1 = 1 x = 1 + 1 x = 2 c) (x – 14) : 2 = 3 x – 14 = 3 . 2 x – 14 = 6 x = 6 + 14 x = 20 d) (30 – x) . 4 = 92 30 – x = 92 : 4 30 – x = 23 x = 30 – 23 x = 7 Chúc học tốt!!! Bình luận
$\text{a, (x – 78) . 25 = 0}$
$\text{x – 78 = 0 : 25}$
$\text{x – 78 = 0}$
$\text{x = 0 + 78}$
$\text{x = 78}$
$\text{b, 37 . (x – 1) = 37}$
$\text{x – 1 = 37 : 37}$
$\text{x – 1 = 1}$
$\text{x = 1 + 1}$
$\text{x = 2}$
$\text{c, (x – 14) : 2 = 3}$
$\text{x – 14 = 3 x 2}$
$\text{x – 14 = 6}$
$\text{x = 6 + 14}$
$\text{x = 20}$
$\text{d, (30 – x) . 4 = 92}$
$\text{30 – x = 92 : 4}$
$\text{30 – x = 23}$
$\text{x = 30 – 23}$
$\text{x = 7}$
a) (x – 78) . 25 = 0
x – 78 = 0 : 25
x – 78 = 0
x = 0 + 78
x = 78
b) 37 . (x – 1) = 37
x – 1 = 37 : 37
x – 1 = 1
x = 1 + 1
x = 2
c) (x – 14) : 2 = 3
x – 14 = 3 . 2
x – 14 = 6
x = 6 + 14
x = 20
d) (30 – x) . 4 = 92
30 – x = 92 : 4
30 – x = 23
x = 30 – 23
x = 7
Chúc học tốt!!!