Tìm x , biết ( làm đầy đủ nhé ) a) (2x +3)(x – 4) + (x – 5)(x – 2) = (3x – 5)(x – 4) b) (8x – 3)(3x +2 ) – ( 4x + 7 )(x + 4) = ( 4x + 1 ) ( 5x – 1 )

Tìm x , biết
( làm đầy đủ nhé )
a) (2x +3)(x – 4) + (x – 5)(x – 2) = (3x – 5)(x – 4)
b) (8x – 3)(3x +2 ) – ( 4x + 7 )(x + 4) = ( 4x + 1 ) ( 5x – 1 )
c) 2x^2 + 3(x – 1)(x + 1 ) = 5x(x + 1 )
d) ( 8 – 5x) ( x + 2 ) + 4(x – 2)(x + 1 ) + ( x – 2 ) ( x + 2 ) = 0
#Làm sai = báo cáo

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  1. Đáp án:

     

    Giải thích các bước giải:

    `a) (2x +3)(x – 4) + (x – 5)(x – 2) = (3x – 5)(x – 4)`

    `⇔ 2x² – 8x + 3x – 12 + x² – 2x – 5x + 10 = 3x² – 12x – 5x + 20`

    `⇔ 2x² + x² – 3x² – 8x + 3x – 2x – 5x + 12x + 5x = 20 + 12 – 10`

    `⇔ 5x = 22`

    `⇔ x = 225`

    `b)  (8x – 3)(3x +2 ) – ( 4x + 7 )(x + 4) = ( 4x + 1 ) ( 5x – 1 )`

    `⇔ 24x² + 16x – 9x – 6 – 4x² – 16x – 7x – 28 = 20x² – 4x + 5x – 1`

    `⇔ 24x² – 4x² – 20x² + 16 x – 9x – 16x – 7x + 4x – 5x = 6 + 28 – 1`

    `⇔ -17x = 33`

    `⇔ x = −3317`

    `c)  2x^2 + 3(x – 1)(x + 1 ) = 5x(x + 1 )`

    `⇔ 2x² + 3( x² – 1 ) = 5x² + 5x`

    `⇔ 2x² + 3x² – 3 = 5x² + 5x`

    `⇔ 2x² + 3x² – 5x² – 5x = 3`

    `⇔ -5x = 3`

    `⇔ x = −35`

    `d) ( 8 – 5x) ( x + 2 ) +4 (x – 2)(x + 1 ) + ( x – 2 ) ( x + 2 ) = 0`

    `⇔ 8x + 16 – 5x² – 10x + 4 ( x² + x – 2x – 2 ) + x² – 4 = 0`

    `⇔ 8x + 16 – 5x² – 10x + 4x² + 4x – 8x – 8 + x² – 4 = 0`

    `⇔ -5x² + 4x² + x² + 8x – 10x + 4x – 8x = 4 + 8 – 16`

    `⇔ -6x = -4`

    `⇔ x = −4−6`

    `⇔ x = 23`

    Xin hay nhất !

     

    Bình luận
  2. a) (2x +3)(x – 4) + (x – 5)(x – 2) = (3x – 5)(x – 4)

    ⇔ 2x² – 8x + 3x – 12 + x² – 2x – 5x + 10 = 3x² – 12x – 5x + 20

    ⇔ 2x² + x² – 3x² – 8x + 3x – 2x – 5x + 12x + 5x = 20 + 12 – 10

    ⇔ 5x = 22

    ⇔ x = $\frac{22}{5}$ 

    b)  (8x – 3)(3x +2 ) – ( 4x + 7 )(x + 4) = ( 4x + 1 ) ( 5x – 1 )

    ⇔ 24x² + 16x – 9x – 6 – 4x² – 16x – 7x – 28 = 20x² – 4x + 5x – 1

    ⇔ 24x² – 4x² – 20x² + 16 x – 9x – 16x – 7x + 4x – 5x = 6 + 28 – 1

    ⇔ -17x = 33

    ⇔ x = $\frac{-33}{17}$ 

    c)  2x^2 + 3(x – 1)(x + 1 ) = 5x(x + 1 )

    ⇔ 2x² + 3( x² – 1 ) = 5x² + 5x

    ⇔ 2x² + 3x² – 3 = 5x² + 5x

    ⇔ 2x² + 3x² – 5x² – 5x = 3

    ⇔ -5x = 3

    ⇔ x = $\frac{-3}{5}$ 

    d) ( 8 – 5x) ( x + 2 ) + 4(x – 2)(x + 1 ) + ( x – 2 ) ( x + 2 ) = 0

    ⇔ 8x + 16 – 5x² – 10x + 4 ( x² + x – 2x – 2 ) + x² – 4 = 0

    ⇔ 8x + 16 – 5x² – 10x + 4x² + 4x – 8x – 8 + x² – 4 = 0

    ⇔ -5x² + 4x² + x² + 8x – 10x + 4x – 8x = 4 + 8 – 16

    ⇔ -6x = -4

    ⇔ x = $\frac{-4}{-6}$ 

    ⇔ x = $\frac{2}{3}$ 

    chúc bạn học tốt

    #anhduongtruong

     

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