tìm căn bậc 2 của 111…1108888..8889(có 99 chữ số 1 và 99 chữ số 8 01/09/2021 Bởi Amaya tìm căn bậc 2 của 111…1108888..8889(có 99 chữ số 1 và 99 chữ số 8
Giải thích các bước giải: $\underset{99}{\underbrace{111….11}}0\underset{99}{\underbrace{88…8}}9=\underset{100}{\underbrace{111….11}}\underset{100}{\underbrace{000…000}}-\underset{100}{\underbrace{111….11}}=\underset{100}{\underbrace{111….11}}(1\underset{100}{\underbrace{00…0}}-1)=\underset{100}{\underbrace{111….11}}.\underset{100}{\underbrace{99…9}}=\underset{100}{\underbrace{111….11}}^2.9\Rightarrow \sqrt{\underset{99}{\underbrace{111….11}}0\underset{99}{\underbrace{88…8}}9}=\sqrt{\underset{100}{\underbrace{111….11}}^2.9}=\underset{100}{\underbrace{33…3}}$ Bình luận
Giải thích các bước giải:
$\underset{99}{\underbrace{111….11}}0\underset{99}{\underbrace{88…8}}9=\underset{100}{\underbrace{111….11}}\underset{100}{\underbrace{000…000}}-\underset{100}{\underbrace{111….11}}=\underset{100}{\underbrace{111….11}}(1\underset{100}{\underbrace{00…0}}-1)=\underset{100}{\underbrace{111….11}}.\underset{100}{\underbrace{99…9}}=\underset{100}{\underbrace{111….11}}^2.9
\Rightarrow \sqrt{\underset{99}{\underbrace{111….11}}0\underset{99}{\underbrace{88…8}}9}=\sqrt{\underset{100}{\underbrace{111….11}}^2.9}=\underset{100}{\underbrace{33…3}}$