Tím đa thức B biết B-(3x^6-4xy^5+1/3xy^2-3/2)=(7x^6-1/2xy^5-xy-1/3) Giúp mk ạ, hứa vote 5⭐ 28/09/2021 Bởi Jasmine Tím đa thức B biết B-(3x^6-4xy^5+1/3xy^2-3/2)=(7x^6-1/2xy^5-xy-1/3) Giúp mk ạ, hứa vote 5⭐
Ta có: `B-(3x^6-4xy^5+1/3xy^2-3/2)=(7x^6-1/2xy^5-xy-1/3)` `⇔ B = (7x^6-1/2xy^5-xy-1/3) + (3x^6-4xy^5+1/3xy^2-3/2)` `⇔ B =7x^6-1/2xy^5-xy-1/3 + 3x^6-4xy^5+1/3xy^2-3/2` `⇔ B = (7x^6 + 3x^6) – (1/2xy^5 + 4xy^5) + 1/3xy^2 – xy – (1/3 + 3/2)` `⇔ B = 10x^6 – 9/2xy^5 + 1/3xy^2 – xy – 11/6`. Bình luận
Đáp án + giải thích bước giải : `B – (3x^6 – 4xy^5 + 1/3xy^2 – 3/2) = 7x^6 – 1/2xy^5 – xy – 1/3` `-> B = 7x^6 – 1/2xy^5 – xy – 1/3 + 3x^6 – 4xy^5 + 1/3xy^2 – 3/2` `-> B = (7x^6 + 3x^6) + (-1/2xy^5 – 4xy^5) -xy + 1/2xy^2 + (-1/3 – 3/2)` `-> B = 10x^6 – 9/2 xy^5 – xy + 1/2xy^2 – 11/6` Bình luận
Ta có:
`B-(3x^6-4xy^5+1/3xy^2-3/2)=(7x^6-1/2xy^5-xy-1/3)`
`⇔ B = (7x^6-1/2xy^5-xy-1/3) + (3x^6-4xy^5+1/3xy^2-3/2)`
`⇔ B =7x^6-1/2xy^5-xy-1/3 + 3x^6-4xy^5+1/3xy^2-3/2`
`⇔ B = (7x^6 + 3x^6) – (1/2xy^5 + 4xy^5) + 1/3xy^2 – xy – (1/3 + 3/2)`
`⇔ B = 10x^6 – 9/2xy^5 + 1/3xy^2 – xy – 11/6`.
Đáp án + giải thích bước giải :
`B – (3x^6 – 4xy^5 + 1/3xy^2 – 3/2) = 7x^6 – 1/2xy^5 – xy – 1/3`
`-> B = 7x^6 – 1/2xy^5 – xy – 1/3 + 3x^6 – 4xy^5 + 1/3xy^2 – 3/2`
`-> B = (7x^6 + 3x^6) + (-1/2xy^5 – 4xy^5) -xy + 1/2xy^2 + (-1/3 – 3/2)`
`-> B = 10x^6 – 9/2 xy^5 – xy + 1/2xy^2 – 11/6`