Tìm lim [(7n^2 – 2n^3 + 1) / (3n^3 + 2n^2 + 1)] 05/11/2021 Bởi Piper Tìm lim [(7n^2 – 2n^3 + 1) / (3n^3 + 2n^2 + 1)]
$\lim\dfrac{7n^2-2n^3+1}{3n^3+2n^2+1}=\lim\dfrac{\dfrac{-2n^3+7n^2+1}{n^3}}{\dfrac{3n^3+2n^2+1}{n^3}}=\lim\dfrac{ -2+\dfrac{7}{n}+\dfrac{1}{n^3}}{3+\dfrac{2}{n}+\dfrac{1}{n^3}}=-\dfrac{2}{3}$ Bình luận
$\lim\dfrac{7n^2-2n^3+1}{3n^3+2n^2+1}$ $=\lim\dfrac{ \dfrac{7}{n}-2+\dfrac{1}{n^3}}{3+\dfrac{2}{n}+\dfrac{1}{n^3}}$ $=\dfrac{0-2+0}{3+0+0}$ $=\dfrac{-2}{3}$ Bình luận
$\lim\dfrac{7n^2-2n^3+1}{3n^3+2n^2+1}=\lim\dfrac{\dfrac{-2n^3+7n^2+1}{n^3}}{\dfrac{3n^3+2n^2+1}{n^3}}=\lim\dfrac{ -2+\dfrac{7}{n}+\dfrac{1}{n^3}}{3+\dfrac{2}{n}+\dfrac{1}{n^3}}=-\dfrac{2}{3}$
$\lim\dfrac{7n^2-2n^3+1}{3n^3+2n^2+1}$
$=\lim\dfrac{ \dfrac{7}{n}-2+\dfrac{1}{n^3}}{3+\dfrac{2}{n}+\dfrac{1}{n^3}}$
$=\dfrac{0-2+0}{3+0+0}$
$=\dfrac{-2}{3}$