Tìm n, biết:
a, ($\frac{2}{3}$) $^{-n+1}$ = ($\frac{3}{2}$)$^{3}$
b, ($\frac{4}{7}$)$^{n+2}$ = $\frac{7}{4}$
Tìm n, biết: a, ($\frac{2}{3}$) $^{-n+1}$ = ($\frac{3}{2}$)$^{3}$ b, ($\frac{4}{7}$)$^{n+2}$ = $\frac{7}{4}$
By Rylee
By Rylee
Tìm n, biết:
a, ($\frac{2}{3}$) $^{-n+1}$ = ($\frac{3}{2}$)$^{3}$
b, ($\frac{4}{7}$)$^{n+2}$ = $\frac{7}{4}$
Ko viết lại đề :(((
a, `=>-n+1=-3`
`=> n = 4`
b, `=> n+2=-1`
`=> n = -3`