tìm số nguyên x sao cho a) (x-1) mủ 2= 0 b)(x-1) mủ 2= 1 12/11/2021 Bởi Vivian tìm số nguyên x sao cho a) (x-1) mủ 2= 0 b)(x-1) mủ 2= 1
Đáp án: $a, (x – 1)² = 0 $ $⇔ x – 1 = 0 $ $⇔ x = 1 $ $b, (x – 1)² = 1 $ $⇔$ \(\left[ \begin{array}{l}(x-1)^{2}=1^{2}\\(x-1)^{2}=(-1)^{2}\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x-1=1\\x-1=-1\end{array} \right.\) $⇔$ \(\left[ \begin{array}{l}x=2\\x=0\end{array} \right.\) Bình luận
`a, (x-1)^2=0` `=> x-1=0` `=> x=0+1` `=> x=1` Vậy `x=1` `b,(x-1)^2=1` `=> (x-1)^2=(±1)^2` `=> x-1=±1` $⇒\left[ \begin{array}{l}x-1=1\\x-1=-1\end{array} \right.$ $⇒\left[ \begin{array}{l}x=1+1\\x=-1+1\end{array} \right.$ $⇒\left[ \begin{array}{l}x=2\\x=0\end{array} \right.$ Vậy `x={2;0}` Bình luận
Đáp án:
$a, (x – 1)² = 0 $
$⇔ x – 1 = 0 $
$⇔ x = 1 $
$b, (x – 1)² = 1 $
$⇔$ \(\left[ \begin{array}{l}(x-1)^{2}=1^{2}\\(x-1)^{2}=(-1)^{2}\end{array} \right.\)
$⇔$ \(\left[ \begin{array}{l}x-1=1\\x-1=-1\end{array} \right.\)
$⇔$ \(\left[ \begin{array}{l}x=2\\x=0\end{array} \right.\)
`a, (x-1)^2=0`
`=> x-1=0`
`=> x=0+1`
`=> x=1`
Vậy `x=1`
`b,(x-1)^2=1`
`=> (x-1)^2=(±1)^2`
`=> x-1=±1`
$⇒\left[ \begin{array}{l}x-1=1\\x-1=-1\end{array} \right.$
$⇒\left[ \begin{array}{l}x=1+1\\x=-1+1\end{array} \right.$
$⇒\left[ \begin{array}{l}x=2\\x=0\end{array} \right.$
Vậy `x={2;0}`