Tìm x thuộc Z dể cho n + 1thuộc UC (-6) Các bạn giúp mình nhé Cám ơn các bạn 06/12/2021 Bởi Raelynn Tìm x thuộc Z dể cho n + 1thuộc UC (-6) Các bạn giúp mình nhé Cám ơn các bạn
$(n+1)\in{Ư(-6)=\{\pm1;\,\pm2;\,\pm3;\,6\}}\\\to \left[\begin{array}{}\hspace{-0,4cm}n+1=1\\n+1=-1\\\hspace{-0,4cm}n+1=2\\n+1=-2\\\hspace{-0,4cm}n+1=3\\n+1=-3\\\hspace{-0,4cm}n+1=6\\n+1=-6\end{array}\right.\\\to \left[\begin{array}{}\hspace{-0,4cm}n=0\\n=-2\\\hspace{-0,4cm}n=1\\n=-3\\\hspace{-0,4cm}n=2\\n=-4\\\hspace{-0,4cm}n=5\\n=-7\end{array}\right.\\\to x\in{\{0;\,-2;\,1;\,-3;\,2;\,-4;\,5;\,-7\}}$ Bình luận
Ư(-6)= -1 ;1;-2;2;-3;6;-6 (n-1)∈Ư(-6) ⇒ n-1=1→n=2 n-1=-1→n=0 n-1=2→n=3 n-1=-2→n=-1 n-1=3→n=4 n-1=-3→n=-2 n-1=6→n=7 n-1=-6→n=-5 vậy n=2;0;3;-1;4;-2;7;-5 Bình luận
$(n+1)\in{Ư(-6)=\{\pm1;\,\pm2;\,\pm3;\,6\}}\\\to \left[\begin{array}{}\hspace{-0,4cm}n+1=1\\n+1=-1\\\hspace{-0,4cm}n+1=2\\n+1=-2\\\hspace{-0,4cm}n+1=3\\n+1=-3\\\hspace{-0,4cm}n+1=6\\n+1=-6\end{array}\right.\\\to \left[\begin{array}{}\hspace{-0,4cm}n=0\\n=-2\\\hspace{-0,4cm}n=1\\n=-3\\\hspace{-0,4cm}n=2\\n=-4\\\hspace{-0,4cm}n=5\\n=-7\end{array}\right.\\\to x\in{\{0;\,-2;\,1;\,-3;\,2;\,-4;\,5;\,-7\}}$
Ư(-6)= -1 ;1;-2;2;-3;6;-6
(n-1)∈Ư(-6)
⇒ n-1=1→n=2
n-1=-1→n=0
n-1=2→n=3
n-1=-2→n=-1
n-1=3→n=4
n-1=-3→n=-2
n-1=6→n=7
n-1=-6→n=-5
vậy n=2;0;3;-1;4;-2;7;-5