tìm x trong tỉ lệ thức sau
a. x – 1 / x + 5 = 7/9
b.x^2/ 6 = 24/25
c. x-2/x-1=x+4/x+7
d. x-3/x+5=5/7
g. x-1/x+2=x-2/x+3
giúp mik vs ạ đg cânf gấp c.ơn trc
tìm x trong tỉ lệ thức sau
a. x – 1 / x + 5 = 7/9
b.x^2/ 6 = 24/25
c. x-2/x-1=x+4/x+7
d. x-3/x+5=5/7
g. x-1/x+2=x-2/x+3
giúp mik vs ạ đg cânf gấp c.ơn trc
Đáp án:
Giải thích các bước giải:
a) ( x – 1 )/( x + 5 ) = 7/9
<-> ( x – 1 ) . 9 = ( x + 5 ) . 7
<-> 9x – 9 = 7x + 35
<-> 9x-7x=9+35
<->2x=44
<-> x = 22
b) x^2/6 = 24/25
<-> x^2 . 25 = 6 . 24
<-> x^2 . 25 = 144
<-> x^2 .5^2=12^2 =(-12)^2
<-> x = 12/5 và x=-12/5
c) ( x – 2 )/( x – 1 ) = ( x + 4 )/( x + 7 )
<-> ( x – 2 )( x + 7 ) = ( x – 1 )( x + 4 )
<-> x^2 + 7x – 2x – 14 = x^2 + 4x – x – 4
<-> 5x – 14 = 3x – 4
<-> 2x = 10
<-> x = 5
d) ( x – 3 )/( x + 5 ) = 5/7
<-> ( x – 3 ) . 7 = ( x + 5 ) . 5
<-> 7x – 21 = 5x + 25
<-> 2x = 46
<-> x = 23
g) ( x – 1 )/( x + 2 ) = ( x – 2 )/( x + 3 )
<-> ( x – 1 )( x + 3 ) = ( x + 2 )( x – 2 )
<-> x^2 – x + 3x – 3 = x^2 – 2^2
<-> 2x – 3 = – 4
<-> 2x = -1
<-> x = -1/2
Bài làm
a) ( x – 1 )/( x + 5 ) = 7/9
<=> ( x – 1 ) . 9 = ( x + 5 ) . 7
<=> 9x – 9 = 7x + 35
<=> 2x = 44
<=> x = 22
Vậy x = 22.
b) x^2/6 = 24/25
<=> x^2 . 25 = 6 . 24
<=> x^2 . 25 = 144
<=> x^2 = 5,76
<=> x = ±2,4
Vậy x =± 2,4.
c) ( x – 2 )/( x – 1 ) = ( x + 4 )/( x + 7 )
<=> ( x – 2 )( x + 7 ) = ( x – 1 )( x + 4 )
<=> x^2 + 7x – 2x – 14 = x^2 + 4x – x – 4
<=> 5x – 14 = 3x – 4
<=> 2x = 10
<=> x = 5
Vậy x = 5.
d) ( x – 3 )/( x + 5 ) = 5/7
<=> ( x – 3 ) . 7 = ( x + 5 ) . 5
<=> 7x – 21 = 5x + 25
<=> 2x = 46
<=> x = 23
Vậy x = 23.
g) ( x – 1 )/( x + 2 ) = ( x – 2 )/( x + 3 )
<=> ( x – 1 )( x + 3 ) = ( x + 2 )( x – 2 )
<=> x^2 – x + 3x – 3 = x^2 – 4
<=> 2x – 3 = – 4
<=> 2x = -1
<=> x = -1/2
Vậy x = -1/2