tim x,y biết a) ( 9/2 – 2/5 : x ) . 13/5 = 13/2 b) | 1/2 . x – 1/3 | = 2/3 17/10/2021 Bởi Piper tim x,y biết a) ( 9/2 – 2/5 : x ) . 13/5 = 13/2 b) | 1/2 . x – 1/3 | = 2/3
a ) ( 9/2 – 2/5 : x ) . 13/5 = 13/2 9/2 – 2/5 : x = 13/2 : 13/5 9/2 – 2/5 : x = 13/2 . 5/13 9/2 – 2/5 : x = 65/26 2/5 : x = 9/2 – 65/26 2/5 : x = 57/26 – 65/26 2/5 : x = -8/26 x = 2/5 : -8/26 x = 2/5 . -26/8 x = -52/40 => x = -13/10 ————————————————————————————————————- b ) I 1/2 . x – 1/3 I = 2/3 1/2 . x – 1/3 = 2/3 1/2 . x = 2/3 + 1/3 1/2 . x = 3/3 1/2 . x = 1 x = 1 : 1/2 x = 1 . 2/1 x = 2/1 x = 2 Ta Có : I 2 I = 2/3 ( Vì Đầu Tiên Ta Biến Đổi ) => Ta Có Hai Trường Hợp : TH1 : I 2 I = 2 => 2 = 2/3 => 2 : 3 = 2 => 0.6 = 2 => 0.6 : 2 = 0.3 TH2 : I 2 I = -2 => -2 = 2/3 => 2 : 3 = -2 => 0.6 = -2 => 0.6 : -2 = -0.3 => x ∈ { 0.3 ; -0.3 } Bình luận
Đáp án: a) $x=\dfrac{2}{10}$ b) $x = \dfrac{2}{3}$ hoặc $x = 2$ Giải thích các bước giải: a) $(\dfrac{9}{2}-\dfrac{2}{5}÷ x).\dfrac{13}{5}=\dfrac{13}{2}$ ⇒ $\dfrac{9}{2}-\dfrac{2}{5}÷ x=\dfrac{13}{2}÷\dfrac{13}{5}$ ⇒ $\dfrac{9}{2}-\dfrac{2}{5}÷ x=\dfrac{13}{2}.\dfrac{5}{13}$ ⇒ $\dfrac{9}{2}-\dfrac{2}{5}÷ x=\dfrac{5}{2}$ ⇒ $\dfrac{2}{5}÷ x=\dfrac{9}{2}-\dfrac{5}{2}$ ⇒ $\dfrac{2}{5}÷ x=\dfrac{4}{2}=2$ ⇒ $x=\dfrac{2}{5}÷2$ ⇒ $x=\dfrac{2}{5}÷\dfrac{2}{1}$ ⇒ $x=\dfrac{2}{5}.\dfrac{1}{2}$ ⇒ $x=\dfrac{2}{10}$ b) $|\dfrac{1}{2}.x-\dfrac{1}{3}| = \dfrac{2}{3}$ ⇒$\dfrac{1}{2}.x-\dfrac{1}{3} = -\dfrac{2}{3}$ hoặc $\dfrac{1}{2}.x-\dfrac{1}{3} = \dfrac{2}{3}$ * TRƯỜNG HỢP 1: $\dfrac{1}{2}.x-\dfrac{1}{3} = -\dfrac{2}{3}$ ⇒ $\dfrac{1}{2}.x = -\dfrac{2}{3}+\dfrac{1}{3}$ ⇒ $\dfrac{1}{2}.x = \dfrac{1}{3}$ ⇒ $x = \dfrac{1}{3}÷\dfrac{1}{2}$ ⇒ $x = \dfrac{1}{3}.\dfrac{2}{1}$ ⇒ $x = \dfrac{2}{3}$ * TRƯỜNG HỢP 2: $\dfrac{1}{2}.x-\dfrac{1}{3} = \dfrac{2}{3}$ ⇒ $\dfrac{1}{2}.x = \dfrac{2}{3}+\dfrac{1}{3}$ ⇒ $\dfrac{1}{2}.x = \dfrac{3}{3}=1$ ⇒ $x = 1÷\dfrac{1}{2}$ ⇒ $x = 1×\dfrac{2}{1}$ ⇒ $x = 2$ Vậy $x = \dfrac{2}{3}$ hoặc $x = 2$ Bình luận
a ) ( 9/2 – 2/5 : x ) . 13/5 = 13/2
9/2 – 2/5 : x = 13/2 : 13/5
9/2 – 2/5 : x = 13/2 . 5/13
9/2 – 2/5 : x = 65/26
2/5 : x = 9/2 – 65/26
2/5 : x = 57/26 – 65/26
2/5 : x = -8/26
x = 2/5 : -8/26
x = 2/5 . -26/8
x = -52/40
=> x = -13/10
————————————————————————————————————-
b ) I 1/2 . x – 1/3 I = 2/3
1/2 . x – 1/3 = 2/3
1/2 . x = 2/3 + 1/3
1/2 . x = 3/3
1/2 . x = 1
x = 1 : 1/2
x = 1 . 2/1
x = 2/1
x = 2
Ta Có : I 2 I = 2/3 ( Vì Đầu Tiên Ta Biến Đổi )
=> Ta Có Hai Trường Hợp :
TH1 : I 2 I = 2
=> 2 = 2/3
=> 2 : 3 = 2
=> 0.6 = 2
=> 0.6 : 2
= 0.3
TH2 : I 2 I = -2
=> -2 = 2/3
=> 2 : 3 = -2
=> 0.6 = -2
=> 0.6 : -2
= -0.3
=> x ∈ { 0.3 ; -0.3 }
Đáp án:
a) $x=\dfrac{2}{10}$
b) $x = \dfrac{2}{3}$ hoặc $x = 2$
Giải thích các bước giải:
a) $(\dfrac{9}{2}-\dfrac{2}{5}÷ x).\dfrac{13}{5}=\dfrac{13}{2}$
⇒ $\dfrac{9}{2}-\dfrac{2}{5}÷ x=\dfrac{13}{2}÷\dfrac{13}{5}$
⇒ $\dfrac{9}{2}-\dfrac{2}{5}÷ x=\dfrac{13}{2}.\dfrac{5}{13}$
⇒ $\dfrac{9}{2}-\dfrac{2}{5}÷ x=\dfrac{5}{2}$
⇒ $\dfrac{2}{5}÷ x=\dfrac{9}{2}-\dfrac{5}{2}$
⇒ $\dfrac{2}{5}÷ x=\dfrac{4}{2}=2$
⇒ $x=\dfrac{2}{5}÷2$
⇒ $x=\dfrac{2}{5}÷\dfrac{2}{1}$
⇒ $x=\dfrac{2}{5}.\dfrac{1}{2}$
⇒ $x=\dfrac{2}{10}$
b) $|\dfrac{1}{2}.x-\dfrac{1}{3}| = \dfrac{2}{3}$
⇒$\dfrac{1}{2}.x-\dfrac{1}{3} = -\dfrac{2}{3}$ hoặc $\dfrac{1}{2}.x-\dfrac{1}{3} = \dfrac{2}{3}$
* TRƯỜNG HỢP 1: $\dfrac{1}{2}.x-\dfrac{1}{3} = -\dfrac{2}{3}$
⇒ $\dfrac{1}{2}.x = -\dfrac{2}{3}+\dfrac{1}{3}$
⇒ $\dfrac{1}{2}.x = \dfrac{1}{3}$
⇒ $x = \dfrac{1}{3}÷\dfrac{1}{2}$
⇒ $x = \dfrac{1}{3}.\dfrac{2}{1}$
⇒ $x = \dfrac{2}{3}$
* TRƯỜNG HỢP 2: $\dfrac{1}{2}.x-\dfrac{1}{3} = \dfrac{2}{3}$
⇒ $\dfrac{1}{2}.x = \dfrac{2}{3}+\dfrac{1}{3}$
⇒ $\dfrac{1}{2}.x = \dfrac{3}{3}=1$
⇒ $x = 1÷\dfrac{1}{2}$
⇒ $x = 1×\dfrac{2}{1}$
⇒ $x = 2$
Vậy $x = \dfrac{2}{3}$ hoặc $x = 2$