Tìm x, y nguyên sao cho: 2x+xy+3y=11 Giúp mik với

xy + 2x – y + 11 = 0

⇔⇔(xy + 2x) + ( – y – 2) = – 13

⇔⇔(y + 2)(x – 1) = –13

⇒⇒(y + 2, x – 1) = (1, – 13; – 13, 1; – 1, 13; 13, – 1)

⇒⇒(y, x) = (- 1, – 12; – 15, 2; – 3, 14; 11, 0)