Tìm x, y nguyên sao cho: 2x+xy+3y=11 Giúp mik với 17/09/2021 Bởi Eden Tìm x, y nguyên sao cho: 2x+xy+3y=11 Giúp mik với
xy + 2x – y + 11 = 0 ⇔⇔(xy + 2x) + ( – y – 2) = – 13 ⇔⇔(y + 2)(x – 1) = –13 ⇒⇒(y + 2, x – 1) = (1, – 13; – 13, 1; – 1, 13; 13, – 1) ⇒⇒(y, x) = (- 1, – 12; – 15, 2; – 3, 14; 11, 0) Bình luận
xy + 2x – y + 11 = 0
⇔⇔(xy + 2x) + ( – y – 2) = – 13
⇔⇔(y + 2)(x – 1) = –13
⇒⇒(y + 2, x – 1) = (1, – 13; – 13, 1; – 1, 13; 13, – 1)
⇒⇒(y, x) = (- 1, – 12; – 15, 2; – 3, 14; 11, 0)