Tìm x, y, z: x:y:z=3:5(-2) và 5x-y+3z=186 24/08/2021 Bởi Raelynn Tìm x, y, z: x:y:z=3:5(-2) và 5x-y+3z=186
Đáp án: $\begin{array}{l}x:y:z = 3:5:\left( { – 2} \right)\\ \Rightarrow \frac{x}{3} = \frac{y}{5} = \frac{z}{{ – 2}}\\ \Rightarrow \frac{x}{3} = \frac{y}{5} = \frac{z}{{ – 2}} = \frac{{5x}}{{15}} = \frac{y}{5} = \frac{{3z}}{{ – 6}} = \frac{{5x – y + 3z}}{{15 – 5 – 6}} = \frac{{186}}{4} = \frac{{93}}{2}\\ \Rightarrow \left\{ \begin{array}{l}x = \frac{{93}}{2}.3 = \frac{{279}}{2}\\y = \frac{{93}}{2}.5 = \frac{{465}}{2}\\z = \frac{{93}}{2}.\left( { – 2} \right) = – 93\end{array} \right.\end{array}$ Bình luận
Đáp án:
$\begin{array}{l}
x:y:z = 3:5:\left( { – 2} \right)\\
\Rightarrow \frac{x}{3} = \frac{y}{5} = \frac{z}{{ – 2}}\\
\Rightarrow \frac{x}{3} = \frac{y}{5} = \frac{z}{{ – 2}} = \frac{{5x}}{{15}} = \frac{y}{5} = \frac{{3z}}{{ – 6}} = \frac{{5x – y + 3z}}{{15 – 5 – 6}} = \frac{{186}}{4} = \frac{{93}}{2}\\
\Rightarrow \left\{ \begin{array}{l}
x = \frac{{93}}{2}.3 = \frac{{279}}{2}\\
y = \frac{{93}}{2}.5 = \frac{{465}}{2}\\
z = \frac{{93}}{2}.\left( { – 2} \right) = – 93
\end{array} \right.
\end{array}$