Tính : ( 3.4.2^16)^2 phần 11.2^13 . 4^11 – 16^9 3^11.11+3^11.21 phần 3^9 . 2^5 11/09/2021 Bởi Rylee Tính : ( 3.4.2^16)^2 phần 11.2^13 . 4^11 – 16^9 3^11.11+3^11.21 phần 3^9 . 2^5
Giải thích các bước giải: `(3.4.2^16)^2/(11. 2^13. 4^11-16^9)``=[3.(2^2).2^16]^2/(11. 2^13. (2^2)^11-(2^4)^9)``=(3^2 . 2^4 . 2^32)/(11. 2^13. 2^22 -2^36)``=(3^2 . 2^36)/(11. 2^35 -2^36)``=(3^2 . 2^36)/(2^35 . (11-2))``=(3^2 . 2^36)/(2^35 . 3^2)``=2``(3^11 .11+3^11 .21)/(3^9 . 2^5)``=(3^11 . (11+21))/(3^9 . 2^5)``=(3^11 . 32)/(3^9 . 2^5)``=(3^11 . 2^5 )/(3^9 . 2^5)``=3^2``=9` Bình luận
$\begin{array}{l}\quad\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\\=\dfrac{\left(3.2^2.2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\\=\dfrac{\left(3.2^{18}\right)^2}{11.2^{13}.2^{22}-2^{36}}\\=\dfrac{3^2.2^{36}}{11.2^{35}-2^{36}}\\=\dfrac{3^2.2^{36}}{2^{35}.(11-2)}\\=\dfrac{9.2^{36}}{2^{35}.9}\\=2\\\,\\\quad\dfrac{3^{11}.11+3^{11}.21}{3^9.2^5}\\=\dfrac{3^{11}.(11+21)}{3^9.32}\\=\dfrac{3^{11}.32}{3^9.32}\\=3^2\\=9 \end{array}$ Bình luận
Giải thích các bước giải:
`(3.4.2^16)^2/(11. 2^13. 4^11-16^9)`
`=[3.(2^2).2^16]^2/(11. 2^13. (2^2)^11-(2^4)^9)`
`=(3^2 . 2^4 . 2^32)/(11. 2^13. 2^22 -2^36)`
`=(3^2 . 2^36)/(11. 2^35 -2^36)`
`=(3^2 . 2^36)/(2^35 . (11-2))`
`=(3^2 . 2^36)/(2^35 . 3^2)`
`=2`
`(3^11 .11+3^11 .21)/(3^9 . 2^5)`
`=(3^11 . (11+21))/(3^9 . 2^5)`
`=(3^11 . 32)/(3^9 . 2^5)`
`=(3^11 . 2^5 )/(3^9 . 2^5)`
`=3^2`
`=9`
$\begin{array}{l}\quad\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\\=\dfrac{\left(3.2^2.2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\\=\dfrac{\left(3.2^{18}\right)^2}{11.2^{13}.2^{22}-2^{36}}\\=\dfrac{3^2.2^{36}}{11.2^{35}-2^{36}}\\=\dfrac{3^2.2^{36}}{2^{35}.(11-2)}\\=\dfrac{9.2^{36}}{2^{35}.9}\\=2\\\,\\\quad\dfrac{3^{11}.11+3^{11}.21}{3^9.2^5}\\=\dfrac{3^{11}.(11+21)}{3^9.32}\\=\dfrac{3^{11}.32}{3^9.32}\\=3^2\\=9 \end{array}$