Tính A= 1/5^2 + 2/5^3 + 3/5^4 +…+ 11/5^12 17/08/2021 Bởi Madelyn Tính A= 1/5^2 + 2/5^3 + 3/5^4 +…+ 11/5^12
Giải thích các bước giải: `A= 1/5^2 + 2/5^3 + 3/5^4 +…+ 11/5^12` `5A= 1/5 + 2/5^2 + 3/5^3 +…+ 11/5^11` `5A-A=(1/5 + 2/5^2 + 3/5^3 +…+ 11/5^11)-(1/5^2 + 2/5^3 + 3/5^4 +…+ 11/5^12)` `4A=1/5 + 1/5^2 + 1/5^3 +…+ 1/5^11-11/5^12` Đặt `B=1/5 + 1/5^2 + 1/5^3 +…+ 1/5^11` `5B=5 + 1/5 + 1/5^2 +…+ 1/5^10` `5B-B=(5 + 1/5 + 1/5^2 +…+ 1/5^10)-(1/5 + 1/5^2 + 1/5^3 +…+ 1/5^11)` `4B=5-1/5^11` `B=(5-1/5^11)/4` `=>4A=(5-1/5^11)/4-11/5^12` `=>A=((5-5/5^12)/4-11/5^12)/4=((5-49)/5^12)/4=-44/(4.5^12)=-11/5^12` Bình luận
Giải thích các bước giải:
`A= 1/5^2 + 2/5^3 + 3/5^4 +…+ 11/5^12`
`5A= 1/5 + 2/5^2 + 3/5^3 +…+ 11/5^11`
`5A-A=(1/5 + 2/5^2 + 3/5^3 +…+ 11/5^11)-(1/5^2 + 2/5^3 + 3/5^4 +…+ 11/5^12)`
`4A=1/5 + 1/5^2 + 1/5^3 +…+ 1/5^11-11/5^12`
Đặt `B=1/5 + 1/5^2 + 1/5^3 +…+ 1/5^11`
`5B=5 + 1/5 + 1/5^2 +…+ 1/5^10`
`5B-B=(5 + 1/5 + 1/5^2 +…+ 1/5^10)-(1/5 + 1/5^2 + 1/5^3 +…+ 1/5^11)`
`4B=5-1/5^11`
`B=(5-1/5^11)/4`
`=>4A=(5-1/5^11)/4-11/5^12`
`=>A=((5-5/5^12)/4-11/5^12)/4=((5-49)/5^12)/4=-44/(4.5^12)=-11/5^12`