Tính : `C= 1/3+1/6+1/24+……+1/192+1/384+1/768` 19/10/2021 Bởi Anna Tính : `C= 1/3+1/6+1/24+……+1/192+1/384+1/768`
Đáp án: Giải thích các bước giải: `C=1/3+1/6+1/12+1/24+….+1/192+1/384+1/768` `2C=2/3+2/6+2/24+…+2/192+2/384+2/768` `2C=2/3+1/3+1/12+…+1/96+1/192+1/384` `2C-C=(2/3+1/3+1/12+…+1/96+1/192+1/384)-(1/3+1/6+1/12+1/24+….+1/192+1/384+1/768)` `C=2/3-1/768` `C=511/768` Bình luận
Đáp án:
Giải thích các bước giải:
`C=1/3+1/6+1/12+1/24+….+1/192+1/384+1/768`
`2C=2/3+2/6+2/24+…+2/192+2/384+2/768`
`2C=2/3+1/3+1/12+…+1/96+1/192+1/384`
`2C-C=(2/3+1/3+1/12+…+1/96+1/192+1/384)-(1/3+1/6+1/12+1/24+….+1/192+1/384+1/768)`
`C=2/3-1/768`
`C=511/768`