Tính √$\frac{8^{10}+4^{10}}{8^{4} + 4^{11} }$

Tính
√$\frac{8^{10}+4^{10}}{8^{4} + 4^{11} }$

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  1. $\sqrt[]{\frac{8^{10}+4^{10}}{8^{4}+4^{11}}}$  

    = $\sqrt[]{\frac{( 2.4)^{10}+4^{10}}{( 2.4)^{4}+4^{11}}}$  

    = $\sqrt[]{\frac{2^{10}.4^{10}+4^{10}}{2^{4}.4^{4}+4^{11}}}$  

    = $\sqrt[]{\frac{2^{2^{5}}.4^{10}+4^{10}}{2^{2^{2}}.4^{4}+4^{11}}}$  

    = $\sqrt[]{\frac{2^{2^{5}}.4^{10}+4^{10}}{2^{2^{2}}.4^{4}+4^{11}}}$  

    = $\sqrt[]{\frac{4^{5}.4^{10}+4^{10}}{4^{2}.4^{4}+4^{11}}}$  

    = $\sqrt[]{\frac{( 4^{5}+1).4^{10}}{4^{6}+4^{11}}}$  

    = $\sqrt[]{\frac{( 4^{5}+1).4^{10}}{( 4^{5+1}.4^{6}}}$  

    = $\sqrt[]{4^{4}}= 4^{2}= 16$ 

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