tính M(x)-N(x)=2x^3-x^4+3x^2-8-(-1+3x^4-2x^3_5x^2) em cảm ơn 09/11/2021 Bởi Reese tính M(x)-N(x)=2x^3-x^4+3x^2-8-(-1+3x^4-2x^3_5x^2) em cảm ơn
Ta có: M(x) – N(x) =2x³-x^4+3x²-8 – (-1+3x^4-2x³-5x²) =-x^4 +2x³ + 3x² – 8 -3x^4 +2x³ + 5x² + 1) = -7x^4 +4x³ +8x²-7 Bình luận
Ta có:
M(x) – N(x)
=2x³-x^4+3x²-8 – (-1+3x^4-2x³-5x²)
=-x^4 +2x³ + 3x² – 8 -3x^4 +2x³ + 5x² + 1)
= -7x^4 +4x³ +8x²-7
$M(x)-N(x)= 2x^3-x^4+3x^2-8+1-3x^4+2x^3+5x^2$
$= 4x^3-4x^4+8x^2-7$