Tính nhanh:2020.2020-2018.2022

Question

cattien · Answer

$2020.2020-2018.2022$   $=2020.2020-(2020-2).(2020+2)$   $=2020.2020-[2020.(2020+2)-2(2020+2)]$   $=2020^2-[2020^2+4040-4040-4]$   $=2020^2-[2020^2-4]$   $=2020^2-2020^2+4$   $=2^2=4$

havu · Answer

2020 . 2020 - 2018 . 2022     = 2020 . 2020 - 2018 . (2020 + 2)     = 2020 . 2020 - (2018 . 2020 + 2018 + 2018)     = 2020 . 2020 - (2018 . 2020 + 2020 - 2 + 2020 - 2)     = 2020 . 2020 - ((2018 + 2) . 2020 - 2 - 2)     = 2020 . 2020 - 2020 . 2020 - 4     = 0 - 4     = -4       Ch&uacute;c học tốt!!!

Tính nhanh:2020.2020-2018.2022

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