Tính nhanh: B=3/3+3/15+3/35+3/63+3/99+3/143 24/09/2021 Bởi Aaliyah Tính nhanh: B=3/3+3/15+3/35+3/63+3/99+3/143
Đáp án: Giải thích các bước giải: B=3/3+3/15+3/35+3/63+3/99+3/143 B= 1 + 3/15+3/35+3/63+3/99+3/143 Đặt A = 3/15+3/35+3/63+3/99+3/143 B = 1 A = 5. (3/15+3/35+3/63+3/99+3/143) A = 5/2. (2/15+2/35+2/63+2/99+2/143) A = 5/2. ( 2/3,5+2/5,7+2/7,9+2/9,11+2/11,13) A = 5/2. ( 1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + 1/9 – 1/11 + 1/11 – 1/13) A = 5/2. ( 1/3 – 1/13) A = 5/2.10/39 A = 50/78 = 25/39 Ta có : = 1 + 25/39 = 39/39 + 25/39 = 64/39 Vậy B = 64/39 Bình luận
B=3/3+3/15+3/35+3/63+3/99+3/143 B = 3 × ( 1/3 + 1/15 + 1/35 + 1/63 + 1/99 + 1/143 ) B = 3 × ( 1/1×3 + 1/3×5 + 1/5×7 + … + 1/11×13 ) B = 3 × ( 1 – 1/3 + 1/3 – 1/5 + 1/5 – 1/7 + … + 1/11 – 1/13 ) B = 3 × ( 1 – 1/13) B = 3 × 12/13 B = 36/13 Bình luận
Đáp án:
Giải thích các bước giải:
B=3/3+3/15+3/35+3/63+3/99+3/143
B= 1 + 3/15+3/35+3/63+3/99+3/143
Đặt A = 3/15+3/35+3/63+3/99+3/143
B = 1
A = 5. (3/15+3/35+3/63+3/99+3/143)
A = 5/2. (2/15+2/35+2/63+2/99+2/143)
A = 5/2. ( 2/3,5+2/5,7+2/7,9+2/9,11+2/11,13)
A = 5/2. ( 1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + 1/9 – 1/11 + 1/11 – 1/13)
A = 5/2. ( 1/3 – 1/13)
A = 5/2.10/39
A = 50/78 = 25/39
Ta có :
= 1 + 25/39 = 39/39 + 25/39 = 64/39
Vậy B = 64/39
B=3/3+3/15+3/35+3/63+3/99+3/143
B = 3 × ( 1/3 + 1/15 + 1/35 + 1/63 + 1/99 + 1/143 )
B = 3 × ( 1/1×3 + 1/3×5 + 1/5×7 + … + 1/11×13 )
B = 3 × ( 1 – 1/3 + 1/3 – 1/5 + 1/5 – 1/7 + … + 1/11 – 1/13 )
B = 3 × ( 1 – 1/13)
B = 3 × 12/13
B = 36/13