Tính tích các đơn thức sau rồi tìm bậc: a)1/2x ² .(-2x ²y ²z).-1/3x ²y ³ b) (-x ²y) ³.1/2x ²y ³.(-2xy ²z) ² 02/11/2021 Bởi Reagan Tính tích các đơn thức sau rồi tìm bậc: a)1/2x ² .(-2x ²y ²z).-1/3x ²y ³ b) (-x ²y) ³.1/2x ²y ³.(-2xy ²z) ²
Đáp án: a)1/2x ² .(-2x ²y ²z).-1/3x ²y ³ =(1/2-2-1/3)x6y5z =-11/6.x6y5z Bậc:12 b) (-x ²y) ³.1/2x ²y ³.(-2xy ²z) ² =(-1+1/2-2)x5y8z2 =-2,5.x5y8z2 Bậc:15 Bình luận
a) $\dfrac{1}{2}x^2.(-2x^2y^2z).\dfrac{-1}{3}x^2y^3$ $=[\dfrac{1}{2}.(-2).\dfrac{-1}{3}].(x^2.x^2.x^2).(y^2.y^3).z$ $=\dfrac{1}{3}x^6y^5z$ Bậc: $6+5+1=12$ b) $(-x^2y)^3.\dfrac{1}{2}x^2y^3.(-2xy^2z)^2$ $=(-1)^3.(x^2)^3.y^3.\dfrac{1}{2}x^2y^3.(-2)^2.x^2.(y^2)^2.z^2$ $=-x^6y^3.\dfrac{1}{2}x^2y^3.4x^2y^4z^2$ $=-2x^{10}y^{10}z^2$ Bậc: $10+10+2=22$ Bình luận
Đáp án:
a)1/2x ² .(-2x ²y ²z).-1/3x ²y ³
=(1/2-2-1/3)x6y5z
=-11/6.x6y5z
Bậc:12
b) (-x ²y) ³.1/2x ²y ³.(-2xy ²z) ²
=(-1+1/2-2)x5y8z2
=-2,5.x5y8z2
Bậc:15
a) $\dfrac{1}{2}x^2.(-2x^2y^2z).\dfrac{-1}{3}x^2y^3$
$=[\dfrac{1}{2}.(-2).\dfrac{-1}{3}].(x^2.x^2.x^2).(y^2.y^3).z$
$=\dfrac{1}{3}x^6y^5z$
Bậc: $6+5+1=12$
b) $(-x^2y)^3.\dfrac{1}{2}x^2y^3.(-2xy^2z)^2$
$=(-1)^3.(x^2)^3.y^3.\dfrac{1}{2}x^2y^3.(-2)^2.x^2.(y^2)^2.z^2$
$=-x^6y^3.\dfrac{1}{2}x^2y^3.4x^2y^4z^2$
$=-2x^{10}y^{10}z^2$
Bậc: $10+10+2=22$