Viết các phương trình phản ứng xảy ra cho các sơ đồ sau:
a. HCl -> Cl2-> FeCl2 -> Nacl -> HCl -> CuCl2-> AgCl
b. KMnO4 -> Cl2 -> HCl -> FeCl2 -> AgCl -> Cl2 -> Br2-> I2
c. KMnO4 -> Cl2 -> HCl -> FeCl2 -> AgCl-> Ag
Mng giúp mk vs ạ, mk cám ơn nhiều :>>
\(\begin{array}{l}
a)\\
4HCl + Mn{O_2} \to MnC{l_2} + C{l_2} + 2{H_2}O\\
C{l_2} + Fe(du) \to FeC{l_2}\\
FeC{l_2} + 2NaOH \to Fe{(OH)_2} + 2NaCl\\
2NaCl + {H_2}S{O_4} \to N{a_2}S{O_4} + 2HCl\\
2HCl + CuO \to CuC{l_2} + {H_2}O\\
CuC{l_2} + 2AgN{O_3} \to 2AgCl + Cu{(N{O_3})_2}\\
b)\\
2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
C{l_2} + {H_2} \to 2HCl\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
FeC{l_2} + 2AgN{O_3} \to 2AgCl + Fe{(N{O_3})_2}\\
2AgCl \to 2Ag + C{l_2}\\
C{l_2} + 2NaBr \to 2NaCl + B{r_2}\\
B{r_2} + 2NaI \to 2NaBr + {I_2}\\
c)\\
2KMn{O_4} + 16HCl \to 2KCl + 2MnC{l_2} + 5C{l_2} + 8{H_2}O\\
C{l_2} + {H_2} \to 2HCl\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
FeC{l_2} + 2AgN{O_3} \to 2AgCl + Fe{(N{O_3})_2}\\
2AgCl \to 2Ag + C{l_2}
\end{array}\)
Đáp án:
Giải thích các bước giải:
a)2HCl->H2+Cl2
2Fe+3Cl2->2FeCl3
FeCl3+3NaOH->3NaCl+Fe(OH)3
2NaCl+H2SO4->Na2SO4+2HCl
CuO+2HCl->CuCl2+H2O
CuCl2+2AgNO3->Cu(NO3)2+2AgCl
b)2KMnO4+16HCl->2KCl+2MnCl2+5Cl2+8H2O
Cl2+H2->2HCl
Fe2O3+6HCl->2FeCl3+3H2O
FeCl3+3AgNO3->Fe(NO3)3+3AgCl
2AgCl->(as) 2Ag+Cl2
Cl2+2KBr->2KCl+Br2
Br2+2HI->2HBr+I2
Zn+I2->ZnI2
c)MnO2+4HCl->MnCl2+Cl2+2H2O
3Cl2+6KOH->5KCl+KClO3+3H2O
2KClO3->2KCl+3O2
2KCl+2H2O->2KOH+Cl2+H2
2Cl2+2Ca(OH)2->CaCl2+Ca(ClO)2+2H2O