Viết pt hóa học của Pu propan 1_ol, propan 2_ol, với a. Natri kim loại b. Cuo ,t°c c. HBr d. CH3OH 30/10/2021 Bởi Quinn Viết pt hóa học của Pu propan 1_ol, propan 2_ol, với a. Natri kim loại b. Cuo ,t°c c. HBr d. CH3OH
Đáp án: Giải thích các bước giải: a. CH3-CH2-CH2-OH + Na —> CH3-CH2-CH2-ONa + 1/2 H2 CH3-CH(OH)-CH3 + Na —> CH3-CH(ONa)-CH3 + 1/2 H2 b. CH3-CH2-CH2-OH + CuO -to-> CH3-CH2-CHO + Cu + H2O CH3-CH(OH)-CH3 + CuO -to-> CH3-CO-CH3 + Cu + H2O c. CH3-CH2-CH2-OH + HBr —>CH3-CH2-CH2-Br + H2O CH3-CH(OH)-CH3 + HBr —> CH3-CH(Br)-CH3 + H2O d. propan-1-ol và propan-2-ol không tác dụng với CH3OH Bình luận
Propan-1-ol: $C{H_3} – C{H_2} – C{H_2}OH$ Propan-2-ol: $C{H_3} – CH(OH )- C{H_3}$ Phương trình hóa học: a. $C{H_3} – C{H_2} – C{H_2}OH + Na \to C{H_3} – C{H_2} – C{H_2}ONa + \dfrac{1}{2}{H_2}$ $C{H_3} – CH(OH) – C{H_3} + Na \to C{H_3} – CH(ONa) – C{H_3} + \frac{1}{2}{H_2}$ b. $C{H_3} – C{H_2} – C{H_2}OH + CuO\xrightarrow{{{t^o}}}C{H_3} – C{H_2} – CHO + Cu + {H_2}O$ $C{H_3} – CH(OH) – C{H_3} + CuO\xrightarrow{{{t^o}}}C{H_3} – CO – C{H_3} + Cu + {H_2}O$ c. $C{H_3} – C{H_2} – C{H_2}OH + HBr \to C{H_3} – C{H_2} – C{H_2}Br + {H_2}O$ $C{H_3} – CH(OH) – C{H_3} + HBr \to C{H_3} – CHBr – C{H_3} + {H_2}O$ d. $C{H_3} – C{H_2} – C{H_2}OH + C{H_3}OH\xrightarrow[{{{140}^o}C}]{{{H_2}S{O_{4\,\,đạc}}}}\\\, \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3} – C{H_2} – C{H_2} – O – C{H_3} + {H_2}O$ $C{H_3} – CH(OH) – C{H_3} + C{H_3}OH\xrightarrow[{{{140}^o}C}]{{{H_2}S{O_{4\,\,đặc}}}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3} – CH(C{H_3}) – O – C{H_3} + {H_2}O$ Bình luận
Đáp án:
Giải thích các bước giải:
a.
CH3-CH2-CH2-OH + Na —> CH3-CH2-CH2-ONa + 1/2 H2
CH3-CH(OH)-CH3 + Na —> CH3-CH(ONa)-CH3 + 1/2 H2
b.
CH3-CH2-CH2-OH + CuO -to-> CH3-CH2-CHO + Cu + H2O
CH3-CH(OH)-CH3 + CuO -to-> CH3-CO-CH3 + Cu + H2O
c.
CH3-CH2-CH2-OH + HBr —>CH3-CH2-CH2-Br + H2O
CH3-CH(OH)-CH3 + HBr —> CH3-CH(Br)-CH3 + H2O
d.
propan-1-ol và propan-2-ol không tác dụng với CH3OH
Propan-1-ol: $C{H_3} – C{H_2} – C{H_2}OH$
Propan-2-ol: $C{H_3} – CH(OH )- C{H_3}$
Phương trình hóa học:
a.
$C{H_3} – C{H_2} – C{H_2}OH + Na \to C{H_3} – C{H_2} – C{H_2}ONa + \dfrac{1}{2}{H_2}$
$C{H_3} – CH(OH) – C{H_3} + Na \to C{H_3} – CH(ONa) – C{H_3} + \frac{1}{2}{H_2}$
b.
$C{H_3} – C{H_2} – C{H_2}OH + CuO\xrightarrow{{{t^o}}}C{H_3} – C{H_2} – CHO + Cu + {H_2}O$
$C{H_3} – CH(OH) – C{H_3} + CuO\xrightarrow{{{t^o}}}C{H_3} – CO – C{H_3} + Cu + {H_2}O$
c.
$C{H_3} – C{H_2} – C{H_2}OH + HBr \to C{H_3} – C{H_2} – C{H_2}Br + {H_2}O$
$C{H_3} – CH(OH) – C{H_3} + HBr \to C{H_3} – CHBr – C{H_3} + {H_2}O$
d.
$C{H_3} – C{H_2} – C{H_2}OH + C{H_3}OH\xrightarrow[{{{140}^o}C}]{{{H_2}S{O_{4\,\,đạc}}}}\\\, \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3} – C{H_2} – C{H_2} – O – C{H_3} + {H_2}O$
$C{H_3} – CH(OH) – C{H_3} + C{H_3}OH\xrightarrow[{{{140}^o}C}]{{{H_2}S{O_{4\,\,đặc}}}}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3} – CH(C{H_3}) – O – C{H_3} + {H_2}O$